0

This is a very newbie post. I think I'm just missing something.
Anyway.
I'm trying to display the contents of one column's field (not column name) specified by the contents of another filed in the same row.

Here I show you my table and what I need:

Enter password: **********
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Your MySQL connection id is 71
Server version: 5.5.8-log MySQL Community Server (GPL)

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Type 'help;' or '\h' for help. Type '\c' to clear the current input statement.

mysql> use interntv;
Database changed
mysql> SELECT * FROM members2;
+----+-------+-------+----------------+-------------------+
| id | user  | pass  | name           | email             |
+----+-------+-------+----------------+-------------------+
| 21 | ADMIN | 7aeb0 | Jakob Neumaier | Jakob@gmail.com   |
| 54 | user1 | da8e0 | Adam Portman   | user1@hotmail.com |
| 13 | user2 | 0f1d3 | Peter Lupica   | user2@live.com    |
+----+-------+-------+----------------+-------------------+
3 rows in set (0.00 sec)

mysql> SELECT name FROM members2 WHERE user = 'admin';
+----------------+
| name           |
+----------------+
| Jakob Neumaier |
+----------------+
1 row in set (0.00 sec)

mysql>

I have tried:

<?php

	define('DB_NAME','interntv');
	define('DB_USER','root');
	define('DB_PASSWORD',''); 
	define('DB_HOST','localhost');

	$mysqllink = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);

	if (!$mysqllink) {
		die('Could not connect: ' . mysql_error());
	}

	$db_selected = mysql_select_db(DB_NAME, $mysqllink);

	if (!$db_selected) {
		die ('Can\'t use ' . DB_NAME . ': ' . mysql_error());
	}

	echo 'Connected successfully<br /><br />';

	echo mysql_query("SELECT name FROM members2 WHERE user = 'admin'");
	
?>

The only output I get is:

Connected successfully

Resource id #4

Can someone help me?

2
Contributors
3
Replies
5
Views
6 Years
Discussion Span
Last Post by Jaklins
1

http://www.w3schools.com/php/php_mysql_select.asp

echo mysql_query("SELECT name FROM members2 WHERE user = 'admin'");

to

$result = mysql_query("SELECT name FROM members2 WHERE user = 'admin'");
while($row = mysql_fetch_array($result))
  {
  echo $row['user'] . " " . $row['pass'];
  echo "<br />";
  }

mysql_close($con);
?>

ect

Edited by G&G Designing: n/a

Votes + Comments
Nice googling skills, I didn't find that link.
0

http://www.w3schools.com/php/php_mysql_select.asp

echo mysql_query("SELECT name FROM members2 WHERE user = 'admin'");

to

$result = mysql_query("SELECT name FROM members2 WHERE user = 'admin'");
while($row = mysql_fetch_array($result))
  {
  echo $row['user'] . " " . $row['pass'];
  echo "<br />";
  }

mysql_close($con);
?>

ect

This doesn't work.
I get these errors:

( ! ) Notice: Undefined index: user in C:\wamp\www\test.php on line 28
Call Stack
# Time Memory Function Location
1 0.0039 372456 {main}( ) ..\test.php:0

( ! ) Notice: Undefined index: pass in C:\wamp\www\test.php on line 28
Call Stack
# Time Memory Function Location
1 0.0039 372456 {main}( ) ..\test.php:0


( ! ) Notice: Undefined variable: con in C:\wamp\www\test.php on line 32
Call Stack
# Time Memory Function Location
1 0.0039 372456 {main}( ) ..\test.php:0

( ! ) Warning: mysql_close() expects parameter 1 to be resource, null given in C:\wamp\www\test.php on line 32
Call Stack
# Time Memory Function Location
1 0.0039 372456 {main}( ) ..\test.php:0
2 0.0286 380232 mysql_close ( ) ..\test.php:32

I erased two last ones by deleting $con.
Then I echoed $row inside the while and it only displayed:
Connected successfully

Array

0

http://www.w3schools.com/php/php_mysql_select.asp

echo mysql_query("SELECT name FROM members2 WHERE user = 'admin'");

to

$result = mysql_query("SELECT name FROM members2 WHERE user = 'admin'");
while($row = mysql_fetch_array($result))
  {
  echo $row['user'] . " " . $row['pass'];
  echo "<br />";
  }

mysql_close($con);
?>

ect

2nd reply.
I've taken a closer look now.
You practically copied the code from the example and pasted my syntax into it.
It was almost working. I just had to erase the $con, and replace "name" with "*" in the mysql query. That little star was the key. That and fetching the array.
But you found the example, which was what I needed, so you get +1 to rep ;-)
Thanks.

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