Member Avatar for tarunfuture

Hello Friends i ahve a drop down in which all the values are coming from the database now i have used ajax and jquery for getting the sub categories in another dropdown and its working fine but the problem is when i am using the name of the select box for insertion it always stores the parent id of the category........Please help me friends i am almost lost my job :-(

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  • Latest Post Latest Post by tarunfuture

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Member Avatar for gamebits

Hello Friends i ahve a drop down in which all the values are coming from the database now i have used ajax and jquery for getting the sub categories in another dropdown and its working fine but the problem is when i am using the name of the select box for insertion it always stores the parent id of the category........Please help me friends i am almost lost my job :-(

With the information you are giving all I can say is something is wrong.

Post the relevant code so we can have a look at it.Thanks.

Member Avatar for tarunfuture 
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />

<title></title>

<script type="text/javascript" src="jquery-1.3.2.js"></script>
<script type="text/javascript" src="jquery.livequery.js"></script>
<script type="text/javascript">

$(document).ready(function() {

    //$('#loader').hide();

    $('.parent').livequery('change', function() {

        $(this).nextAll('.parent').remove();
        $(this).nextAll('label').remove();

        $('#show_sub_categories').append('<img src="loader.gif" style="float:left; margin-top:7px;" id="loader" alt="" />');

        $.post("get_chid_categories.php", {
            parent_id: $(this).val(),
        }, function(response){

            setTimeout("finishAjax('show_sub_categories', '"+escape(response)+"')", 400);
        });


        return false;
    });
});

function finishAjax(PID, response){
  $('#loader').remove();

  $('#'+PID).append(unescape(response));
} 

function alert_id()
{
    if($('#sub_category').val() == '')
    alert('Please select a category.');
    else
    alert($('#sub_category').val());
    return false;
}

</script>
<style>
.both h4{ font-family:Arial, Helvetica, sans-serif; margin:0px; font-size:14px;}
#search_category_id{ padding:3px; width:200px;}

.parent{ padding:3px; width:150px; float:left; margin-right:12px;}
.both{ float:left; margin:0 0px 0 0; padding:0px;}
</style>
</head>
<?php
        include('config/databse_config.php');?>
<body>
<form action="" method="get" onsubmit="return alert_id();">
<div style="padding-left:30px; height:710px;">

    <br clear="all" /><br clear="all" />

    <div id="show_sub_categories">
        <select name="search_category" class="parent">
        <option value="" selected="selected">-- Categories --</option>
        <?php
        $query = "SELECT CategoryID, Name, Discount_percent, Discount_flat, Description, PID 
FROM slenrjrt_shopping.Category where PID = 0";
        $results = mysql_query($query);

        while ($rows = mysql_fetch_assoc(@$results))
        {?>
            <option value="<?php echo $rows['CategoryID'];?>"><?php echo $rows['Name'];?></option>
        <?php
        }?>
        </select>    

    </div>
    <div><input type="submit" name="sub" /></div>
    <br clear="all" /><br clear="all" />

</div>
</form>
</body>
</html>
Edited by Dani because: Formatting fixed
Member Avatar for tarunfuture

and my code for getting the child category is here get_chid_categories.php

<?php

include('config/databse_config.php');

if($_REQUEST)
{
    $id     = $_REQUEST['parent_id'];

    $query = "SELECT CategoryID, Name, Discount_percent, Discount_flat, Description, PID 
FROM slenrjrt_shopping.Category where PID = ".$id;
    $results  = @mysql_query( $query);
    $num_rows = @mysql_num_rows($results);
    if($num_rows > 0)
    {?>
        <select name="sub_category" class="parent" id="sub_category">
        <option value="" selected="selected">-- Sub Category --</option>
        <?php
        while ($rows = mysql_fetch_assoc(@$results))
        {?>
            <option value="<?php echo $rows['CategoryID'];?>"><?php echo $rows['Name'];?></option>
        <?php
        }?>
        </select>
        <input type="hidden" name="subcat" value="<?php echo $_REQUEST['sub_category']; ?> " />
    <?php    
    }
    else{echo '<label style="padding:7px;float:left; font-size:12px;">No Record Found !</label>';}
}
?>
Edited by Dani because: Formatting fixed
Member Avatar for tarunfuture

i am not getting my the subcategory id

Member Avatar for gamebits

try:

$query = "SELECT CategoryID, Name, Discount_percent, Discount_flat, Description, PID
FROM slenrjrt_shopping.Category where PID = '$id'";
Member Avatar for tarunfuture

Thanks gamebits for reply but the problem is that i can not select the value of 2nd drop down because i have to store the category id again in the database.

Member Avatar for tarunfuture

Please friends give me some solution of my problem

Member Avatar for tarunfuture

Can Anyone help me in my code

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