I am workin on an project.in which i need to know in what order array is sorted after sortig using function sort(\$array);

This function sorts an array. Elements will be arranged from lowest to highest when this function has completed.

Hmm, maybe I'm not understanding your question, can you please post your code and spot the problem?

## All 7 Replies

This function sorts an array. Elements will be arranged from lowest to highest when this function has completed.

i think their is no solution for it.

Hmm, maybe I'm not understanding your question, can you please post your code and spot the problem?

if i am having the array \$ab=array('0'=>'10','1'=>'5','2'=>'8') .and i sorts it using the array by \$ba=sort(\$ab); then i need two result 1st (5,8,10) and second (1,2,0).the second is order inwhich the values is arranged.

For that you need `asort()`:

``````\$ab = array('0'=>'10','1'=>'5','2'=>'8');
\$ba = \$ab;
asort(\$ba);
print_r(\$ba);
``````

And you get:

``````Array
(
 => 5
 => 8
 => 10
)
``````

but how can i get the 1st value of the sorted array?i cant use \$ba for 5.

A foreach loop will work:

``````foreach(\$ab as \$k => \$v)
{
echo "\$k  -  \$v \n";
}
``````

If you wan to group them in different arrays then use:

``````\$keys = array();
\$values = array();
foreach(\$ab as \$k => \$v)
{
\$keys[] = \$k;
\$values[] = \$v;
}

print_r(\$keys);
print_r(\$values);
``````

Or better use array_keys() and array_values():

``````\$ab = array('0'=>'10','1'=>'5','2'=>'8');
\$ba = \$ab;
asort(\$ba);

print_r(array_keys(\$ba));
print_r(array_values(\$ba));
``````

Ok?

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