compare array elements and return couunt

[jenny1975]

I have 2 arrays that I need to compare against each other and retun the count of the same:

ex: array1[abcd] array2 [adce] return would be 2 as both a and c are in same postion.

I would then have to return 2,1 as a and c are in the same place but d is in the array but in the wrong place.

     var  index = 0;

     for(index = 0; index < length; index++){
     if(array1[index] == array2[index]){
     count++
    } 

return count
}

which i ofcourse is only returning 1, so not sure where to go from here?

[|-|x]

you're missing a brace so the for loop will always return on the first iteration.

    for(index = 0; index < length; index++){
        if(array1[index] == array2[index]){
            count++
        }
    } //<-- add this brace and see if that fixes it.
    return count
}

[jenny1975]

Sorry I just missed it out in the example, but have it in, so that doesn't seem to be the problem.
I am thinking that it has to do with my for() index< lenght; as it is returning 1, which tells me that it is saying the length is the same. I could be wrong , I am new to javascript. So what I need it to do is compare individual elements and return those counts.... number for correct and number for correct and in wrong place. Does this make sense?

[|-|x]

the comparison you have should tell you the exact matches (though you are missing ;'s off the end of lines 5 & 8 (javascrip is a little forgiving if its the last line in a block).

You will have to have a nested loop to do the "correct but in wrong place" check.

Are you able to post any more code, the snippet posted above is obviously only a portion and it would be easier to help spot the issue if you can provide the whole function.

[jenny1975]

Thank you Hearth, you are right, once I fixed it up, it worked jsut the way I wanted it to. Thanks you :)

[|-|x]

Great! No worries, glad I could help. Can you make this thread as solved please? thx