## Featured Replies in this Discussion

- by VernonDozierThere's nothing specifying that the numbers have to be positive. In that case, there are an infinite number of solutions, or since we're talking computer, "billyuns and billyuns" of them as our favorite astronomer used to say. v = w = x = 3. y and z and arithmetic inverses of each other (1, -1), (2, -2), (3, -3), etc so their reciprocals add to zero and they drop out. That's four billion right there.…
- by mike_2000_17

There's nothing specifying that the numbers have to be positive. In that case, there are an infinite number of solutions, or since we're talking computer, "billyuns and billyuns" of them as our favorite astronomer used to say. v = w = x = 3. y and z and arithmetic inverses of each other (1, -1), (2, -2), (3, -3), etc so their reciprocals add to zero and they drop out. That's four billion right there. There are 5 choose 2 = 10 ways of picking which pair of variables are arithmetic inverses, so make it 40 billion and I'm just getting warmed up. Shall we change the problem to requiring the integers to all be positive?

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