Hi How can I subnet this ip address? 100.20.10.0/24 Subnet A 2 hosts Subnet B 80 hosts http://puu.sh/l2ata/3b2d1e6d68.jpg I think my solution not correct! I appricate your help N ID Subnetmask First available Last available Broadcast 100.20.10.128 255.255.255.128 100.20.10.129 PC B 120.10.10.130 120.10.10.131 100.20.10.132 255.255.255.252 100.20.10.132 PC A 100.20.10.134 100.20.10.135 100.20.10.136

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Hi! I am learning about subnet mask. How should I get 12th subnet from this 190.0.0.0/20 IP address? To do it I guess first of all I have to know block address of 20. Ok block address of 20 is 16. So 256 - 16 = 240. So subnet mask address will be 255.255.240.0. So what will be IP range like 190.0.?.0 ? 1 ? 2 ? 3 ? 4 . . . . . . ?/? X 255/256 I have seen an example which is 172.16.0.0/19 Block size of 19 is 32. Subnet mask : 256-32 = 224 so …

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Ok this may be alot to take it at first, but stay with it... I am head of IT at a community centre, and i want to set up DHCP role on a Windows server 2008 32bit Server. The server currently has 1 static ip, and gets it's internet from a standard router, and lets say that is adapter 1. I have installed another network card in it, which i intend to provide and connection for all the client PC's, which are running off a switch. The DHCP going from adapter 2 i want to have a different subnet. So …

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[Click Here](http://i46.tinypic.com/1t3or6.jpg) [Picture is here](http://i46.tinypic.com/1t3or6.jpg "Piture of my network setup") I am in 4 floor Building. See diagram attached. Each floor is divided into 2 sides “F” & “B”, F=left & B=right. And each side has a 24-port 3com super stack III 3226 switch (S1-S7). And each switch per side has up to 28 user/pc. Each floor has 2 printers one on each side, HP Lasejet 4200 (P1-P7). And one HP Color LaserJet CP3525 in the server room (P8). Each switch is connect via fiber to a main switch in a server room “netgear gsm 7312” (S8). I have 17 …

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Picture: http://i1144.photobucket.com/albums/o493/NoCodeMonkey/SAM_0069.jpg Ok so Im confused, In the pic I have 2 vlans (VLAN2, and VLAN3) and the network address of this network is 192.168.0.0. Router has an ip address of 192.168.0.1 for fa0/0, and is connected to VLAN1 (the default) to f0/5 with an ip address of 192.168.0.2 for VLAN1. When i have VLAN2 and VLAN3 do i have to give them a different address for a different network [EX. VLAN2 = 192.168.1.0] and give the hosts on that network that network rage of addresses?

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I can subnet and im going for my CCENT exam Aug 20 and im a little stuck on this question, can someone show me in a really easy way on how the answer is got. I know the answer is 192.168.1.22 but how?: What is the last Usable host address on the third subnet for the following address and mask combination - 192.168.1.0 255.255.255.248?

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I have 2 subnets on my network, 192.168.10.x and 192.168.30.x. 192.168.30.x can ping .10.x and print from the printers on .10.x but 192.168.10.x can not ping or print from the other subnet (.30.x) 192.168.30.x --- GW - 192.168.30.4 192.168.10.x ----- GW - 192.168.10.5 Does anyone have an idea what am doing wrong? Thanks

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Hi, I am a bit confused, I have been given an address 132.132.0.0/16 and i have to devise a scheme allowing for at least 396 subnets. I think i have to extend the subnet mask to do this, I have worked through the different possible masks and the mask /25 gives me a possible 512 subnets this fits into the criteria i was to use. As there is 9 bits left, to find the number of hosts per subnet mask I use the formula 2^9 = 126 hosts, so the first address for the subnet mask 0 is Subnet 0 …

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The network IP address allocated to a network administrator is 172.31.0.0/20. Which portion of the address is the network, which part is the host and which is the subnet mask? n = network s = subnet h = host nnnnnnnn.nnnnnnnn.nnnnssss.hhhhhhhh would that bet correct?

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I have a gateway<->gateway IPSEC VPN running between 2 offices and the first gateway (BiPAC 7404VGO) will also host PPTP VPN connections as well. I need to be able to route PPTP traffic with a destination to the second gateway through the gateway VPN to services in that second network. At this stage no routing occurs when trying to access the second office subnet from the PPTP VPN. All clients are using Windows XP or above and there is an SBS2003 server on the first subnet attached to the first gateway. At this point I have a choice of using …

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The End.