Also, each subquery requires an alias, for example:
select a.total from (select count(*) as total from tablename) as a;
Otherwise you get an error, to see it use mysql_error()
. In addition try this query:
$query=mysql_query("select a.total + b.total as total from (select count(*) as total from message_believe as mb where mb.uid_fk = {$uid}) as a, (select count(*) as total from review_believes as rb where rb.uid_fk = {$uid}) as b") or die(mysql_error());
Bye!