Posts by nav33n Page 36

Why do you want to create a table from php anyway ? Everytime you run your script, it will include table_create.php and tries to create the table all the time. Check this link . Add 'if not exists' in your create table query.

Databases mysql

nav33n 472 Purple hazed!

17 Years Ago

Re: Data retrieve and display help needed

<html>
<head>
<script type="text/javascript">
function addElement() {
  var ni = document.getElementById('myDiv');
  var numi = document.getElementById('theValue');
  var num = (document.getElementById('theValue').value -1)+ 2;
  numi.value = num;
  var newinput = document.createElement('input');
  var divIdName = 'my'+num+'input';
  newinput.setAttribute('id',divIdName);
  newinput.innerHTML = 'Element Number '+num+' has been added! <a href=\'#\' onclick=\'removeElement('+divIdName+')\'>Remove the div "'+divIdName+'"</a>';
  ni.appendChild(newinput);
}
</script>
</head>
<body>
<input type="hidden" value="0" id="theValue" />
<p><a href="javascript:;" onclick="addElement();">Add Some Elements</a></p>
<div id="myDiv"> </div>
</table>
</body>
</html>

To add another table, you need to modify the function.

Web Development php

nav33n 472 Purple hazed!

17 Years Ago

Re: Count Down Game

-914

Geeks' Lounge posting-games

nav33n 472 Purple hazed!

17 Years Ago

Re: PHP Searching Problem...

Then your query is wrong. What exactly are you trying to do with that query ?

Web Development php

nav33n 472 Purple hazed!

17 Years Ago

Re: check box enable button

<html>
<head>
<script type="text/javascript">
function enableButton() {
	if(document.getElementById('option').checked){
		document.getElementById('edit').disabled='';
	} else {
		document.getElementById('edit').disabled='true';
	}
}
</script>
 </head>
<body onload="enableButton();">
<form method="post" action="test5.php">
<input type="checkbox" name="option"  id="option" onclick="javascript:enableButton();">Enable<br>
<input type="button" name="button" value="Edit" id="edit">
</form>
</body>
</html>

Cheers,
Naveen

Web Development php

nav33n 472 Purple hazed!

17 Years Ago

Re: Hi there

:) Welcome!

Say Hello!

nav33n 472 Purple hazed!

17 Years Ago

Re: Introduction

Welcome to Daniweb Riptorn !

Say Hello!

nav33n 472 Purple hazed!

17 Years Ago

Re: hi

Welcome to Daniweb :)

Say Hello!

nav33n 472 Purple hazed!

17 Years Ago

Re: Login session

Same error ? Try mysql_error() with die statement. Also print out your query and tell us what it says !

Web Development php

nav33n 472 Purple hazed!

17 Years Ago

Re: PHP Searching Problem...

SELECT * FROM details WHERE '$_POST[metode]' LIKE '$_POST[search]'% LIMIT 0, 50

I guess $_POST is the column name ? Print out the query, execute it in phpmyadmin/ mysql console. Check the result. Oh, also, remove the @ symbol from

$row = @mysql_fetch_array($query)

Web Development php

nav33n 472 Purple hazed!

17 Years Ago

Re: php: populating 3 listboxes

Tutorial, umm..not sure.. But it can be done using ajax.. In javascript, it can be done this way.
Populate 1st dropdown from the database, have an onchange event for the dropdown. Onchange, submit the page. On submit, you can access the value of 1st dropdown, Eg. $value = $_POST['dropdown1']; Then populate the 2nd dropdown using $value as the condition. Do the same with the 3rd one.

Cheers,
Naveen

Web Development php

nav33n 472 Purple hazed!

17 Years Ago

Re: Fantastic word game

August has 31 days.

Geeks' Lounge posting-games

nav33n 472 Purple hazed!

17 Years Ago

Re: form coding

<html>
<body>
<form method="post" name="test">
<input type="button" name="button1" value="login" onClick="javascript: 

document.test.action='login.php';document.test.submit();"><input type="button" name="button2" value="Register" 

onClick="javascript: document.test.action='register.php';document.test.submit();">
</form>
</body>
</html>

You can do it this way.

Web Development php

nav33n 472 Purple hazed!

17 Years Ago

Re: Count Down Game

-909

Geeks' Lounge posting-games

nav33n 472 Purple hazed!

17 Years Ago

Re: Open Webcam Application

I dont think that can be done using php. As sDjh has already mentioned, try that in java/flash or in .NET !

Web Development php

nav33n 472 Purple hazed!

17 Years Ago

Re: Login session

$query = "SELECT address_code FROM address WHERE userID= '".$myuserID."'";
$result = mysql_query($query);

<td><input type="text" name="PickupAddressPostCode" value="<?php echo $result['address_code']; ?>" /></td>

Matti Ressler
Suomedia

That should actually be

$query = "SELECT address_code FROM address WHERE userID= '".$myuserID."'";
$result = mysql_query($query);
$row = mysql_fech_array($result); //or while($row = mysql_fetch_array($result)) if your query returns more than 1 row
<td><input type="text" name="PickupAddressPostCode" value="<?php echo $row['address_code']; ?>" /></td>

Cheers,
Naveen

Web Development php

nav33n 472 Purple hazed!

17 Years Ago

Re: please to assist me

Welcome to Daniweb :)

Say Hello!

nav33n 472 Purple hazed!

17 Years Ago

Re: Hi

Welcome to Daniweb !

Does this site deals with g.i.f images and skin designs???

You need to be more specific my friend :)

Say Hello!

nav33n 472 Purple hazed!

17 Years Ago

Re: why use @

@ doesn't help it error handling, but it supresses the errors.

if(@mysql_num_rows($result) > 0){ //do something

This above code, supresses the warning if there is something wrong with the query. Its not a good practice to have @, because it makes your life very difficult to know where the exact error is.

Web Development php

nav33n 472 Purple hazed!

17 Years Ago

Re: Count Down Game

-907

Geeks' Lounge posting-games

nav33n 472 Purple hazed!

17 Years Ago

Re: What am I forgetting?

nav33n: It's been like this for the past month. I'm running a test to see if it increases the number of people who search before they post. Additionally, DaniWeb visitors who use our search feature end up spending more than 5X longer on our site than users who don't search, so that's another reason I'm trying to put more emphasis on that section.

Cool ! :)

Meta DaniWeb

nav33n 472 Purple hazed!

17 Years Ago

Re: hello

Hello shello ! Welcome to Daniweb ! Check this forum and post your question in a relevant forum !

Say Hello!

nav33n 472 Purple hazed!

17 Years Ago

Re: Recommended books?

I always checked out SAMS publications for 'quick learning' !

Databases mysql

nav33n 472 Purple hazed!

17 Years Ago

Re: Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in /home

Nope. Just print out the query. ie., instead of

$display = mysql_query("SELECT * FROM $table ORDER BY id",$db);

do,

$query="SELECT * FROM $table ORDER BY id";
echo $query;
$display = mysql_query($query,$db);

Execute your query in phpmyadmin/mysql console and see what's the problem. Or, you can also try putting die statement after mysql_query to see the error.

$display = mysql_query($query,$db) or die(mysql_error());

Web Development mysql php

nav33n 472 Purple hazed!

17 Years Ago

Re: Count Down Game

-903

Geeks' Lounge posting-games

nav33n 472 Purple hazed!

17 Years Ago

Re: Hello all

Welcome to Daniweb!

Say Hello!

nav33n 472 Purple hazed!

17 Years Ago

Re: newbie here....^_^

Welcome herms14 ! :)

Say Hello!

nav33n 472 Purple hazed!

17 Years Ago

Re: Hello all

Welcome to Daniweb!

Say Hello!

nav33n 472 Purple hazed!

17 Years Ago

Re: Hi

Welcome :)

Say Hello!

nav33n 472 Purple hazed!

17 Years Ago

Re: javascript function

I got your PM. I couldn't reply you back cuz maybe you have disabled PM. Anyways, good luck !

Web Development javascript php

nav33n 472 Purple hazed!

17 Years Ago

Re: What am I forgetting?

offtopic, But the font used in search box doesn't look too good. The font size is large. Please check the screenshot!

Meta DaniWeb

nav33n 472 Purple hazed!

17 Years Ago

Re: Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in /home

3 $display = mysql_query("SELECT * FROM $table ORDER BY id",$db);

Select * from $table ? What does $table have ? It must be empty.

Web Development mysql php

nav33n 472 Purple hazed!

17 Years Ago

Re: javascript function

<?php
session_start();
?>
<html>
<head>
<script type="text/javascript">
function login() {
	alert('<?php echo $_SESSION['un']; ?>');
}
</script>
</head>
<body bgcolor="#f1f3f3">
<form method="post" onsubmit="javascript:login();">
<?php
$g=hi;
$_SESSION["un"]=$g;
?>
<input type="submit" name="submit" value="Submit">
</form>
</body>
</html>

Try this. Btw, you didn't have session_start in your script.

Web Development javascript php

nav33n 472 Purple hazed!

17 Years Ago

Re: Poulate a option field on change

Yes. You can do it without using ajax. This is how it is. You populate one select box from the table. Then have an onchange event, which submits the page when an option is selected. Then get the posted selectbox value and populate the 2nd selectbox.

Web Development php

nav33n 472 Purple hazed!

17 Years Ago

Re: Count Down Game

-900

Geeks' Lounge posting-games

nav33n 472 Purple hazed!

17 Years Ago

Re: javascript function

It is possible. But you can do it this way.

<script type='text/javascript'>
alert(<?php echo $_SESSION['un']; ?>);
</script>

If that doesn't work, try, alert('<?php echo $_SESSION['un']; ?>'); Cheers,
Naveen

Web Development javascript php

nav33n 472 Purple hazed!

17 Years Ago

Re: creating a sticky form compatible with onChange

Then your code seems ok ! I dont see any problem..

Web Development php

nav33n 472 Purple hazed!

17 Years Ago

Re: Problem with INSERT command into MySQL

What IS this nasty script? I answered the same to very similar looking code just the other day :icon_eek:

Matti Ressler
Suomedia

Deja vu man ;)

Web Development mysql php

nav33n 472 Purple hazed!

17 Years Ago

Re: mysql

hello
i am using Mysql plse
send DataBase Connection and ROOt

The default user for mysql is root. Database connection can be established by using mysql_connect.
You should be specific in the questions you ask and post your question in related forum !

Databases mysql

nav33n 472 Purple hazed!

17 Years Ago

Re: Simple Code needs fixing

Use is_numeric instead of is_int :) !

Web Development php

nav33n 472 Purple hazed!

17 Years Ago

Re: Simple Code needs fixing

What are you doing btw ? $letter2 will have the first character of $letter. And, it works for me!

$letter2 = $letter{0};

Web Development php