Can anyone send me a simple, understandable javascript code for form validation, including e-mail validation,name validation , password validation etc. pls! send me in hurry!!!:'(
Why the warning is showing and the header is not sendingwith this script?
<?php function authenticateUser($user,$password) { $con=mysql_connect("localhost","root",""); mysql_select_db("niladri",$con); $sql="select * from user_profile where user_id='$user'and password='$password'"; $res=mysql_query("$sql",$con); if( ($row = mysql_fetch_array($res)) && ($user_id==$row["user"])&&($password == $row["password"] ) && ($password !="") ) return 1; else return 0; } ?> <?php $form_user_id=$_POST; $form_password=$_POST; if(authenticateUser($form_user_id,$form_password)) { echo"Your userID and password are correct"; setcookie("cookie_passwd",$form_password,time()+3600); setcookie("cookie_user",$form_user_id,time()+3600); header("Location:search.html"); exit(); } else { echo"the page cannot be displayed/the password and or userID is not correct"; } ?>
The warnings are:
Your userID and password are correct Warning: Cannot modify header information - headers already sent by (output started at C:\Program Files\xampp\htdocs\Niladri's PHP Programs\PROJECT SHOP\index\login1.php:19) in C:\Program Files\xampp\htdocs\Niladri's PHP Programs\PROJECT SHOP\index\login1.php on line 20
Warning: Cannot modify header information - headers already sent by (output started at C:\Program Files\xampp\htdocs\Niladri's PHP Programs\PROJECT SHOP\index\login1.php:19) in C:\Program Files\xampp\htdocs\Niladri's PHP Programs\PROJECT SHOP\index\login1.php on line 21
Warning: Cannot modify header information - headers already sent by (output started at C:\Program Files\xampp\htdocs\Niladri's PHP Programs\PROJECT SHOP\index\login1.php:19) in C:\Program Files\xampp\htdocs\Niladri's PHP Programs\PROJECT SHOP\index\login1.php on line 22
<bodybgcolor="#FFFF00"><divalign="center"><tablewidth="284"border="4"cellspacing="2"cellpadding="2"><tr><tdwidth="92">cat_id</td><tdwidth="79">cat_name</td><tdwidth="79">choose product </td></tr><?php$id=$_GET['id'];$con=mysql_connect("localhost","root","");mysql_select_db("niladri",$con);$sql="SELECT * FROM `subcategory`whare `cat_id`=`$id`";$res=mysql_query("$sql",$con);while($row=mysql_fetch_array($res)){?><tr><td><?phpecho$row[subcat_id];?></td><td><?phpecho$row[subcat_name];?></td><td><ahref="fetch3.php"?id=<?phpecho$row[subcat_id]?>>click</a></td></tr><?php}?></table></div></body>
it is showing an warning--->
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in C:\Program Files\htdocs\Niladri's PHP Programs\PROJECT\fetch2.php on line 16
the previous page fetch1.php code is.....
<?phpob_start();session_start();$sidf=session_id();session_register('sidf');?><bodybgcolor="#FFFF00"><divalign="center"><tablewidth="284"border="4"cellspacing="2"cellpadding="2"><tr><tdwidth="92">cat_id</td><tdwidth="79">cat_name</td><tdwidth="79">choose subcategory </td></tr><?php$con=mysql_connect("localhost","root","");mysql_select_db("niladri",$con);$sql="SELECT * FROM `category`";$res=mysql_query("$sql",$con);while($row=mysql_fetch_array($res)){?><tr><td><?phpecho$row['cat_id'];?></td><td><?phpecho$row['cat_name'];?></td><td><a href="fetch2.php"?id=<?phpprint$row['cat_id'];?>">click</a></td></tr><?php}?></table></div></body>
Can anyone tell me the name of the websites from where i can get the free website design templates!! including flash files!! and many more!! pls. send all the possible links!!! i am not getting the satisfactory design templates!!!!!!:(
pls help me!! why this code is not executing?also send me the exact code to fetch a table from a database in a table format in a web page!!!!!
<?php$con=mysql_connect("localhost","root","");mysql_select_db("niladri",$con);$sql="SELECT *
FROM `category` ";$res==mysql_query($sql);while($row==mysql_fetch_array($res));{echo$row['cat_id'];echo$row['cat_name'];}?>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <title>Untitled Document</title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"> </head>
<body> <?php echo"Your posted name is\t".$_POST; echo"Your posted roll is\t".$_POST; ?> <?php $con=mysql_connect("localhost","root",""); if(!$con) { die("could not connect:".mysql_error($con)); } mysql_select_db("form",$con); mysql_query("insert into submit values('$_POST','$_POST')"); echo"1 record added"; mysql_close($con); ?> </body> </html> error is showing on that line..........
