In my home network I have my desktop wired (eth0) to a Netgear range extender that is wirelessly linked to my Linksys AC1200 router. If I do ip route show I get the IP address of my router but not the Netgear range extender that has the association with the router. How can I get the IP address of the Netgear device?
Gribouillis where did the parameter mode come from in the else return line? I don't see it defined.
woooee Your program is working but it's giving me really messy output, it's all on one line an run togather. I tried pring '\n' right after the print statement but that doesn't seem to be getting the job done. Any ideas?
Is there a function that I can use to find out if a file is a block device? And another for a character device. I'm trying to create a funtion that will build a string the is exactly like the result you get from running ls -l for a slightly larger program I'm working on. Maybe it would save me some time if that function already existed, what would be helpful as well. Thanks.
This is the line in apache's configure file that creates the error.log file. I couldn't find any other references as to what ErrorLog is or how it works. If this had been a touch command or another known command I would be able to get this done pretty easily. Any ideas?
#!/usr/bin/python3
import os, stat, pwd
def list_files():
thisDir = os.listdir()
for current in thisDir:
print(get_current_attr(current))
#print(current)
def get_current_attr(file):
line = (stat.filemode(os.stat(file).st_mode))
line = line + '\t\t ' + (stat.filemode(os.stat(file).st_uid))
line = line + '\t\t ' + file
return line
print(list_files())
#END#
Why is the second line in get_current_attr() dispaying almost the exact same thing as the frist line except that it lacks the tail end None, which I atually prefer. I changed st_mode to st_uid but I'm still getting almost the same output. Thanks Woooee, I'' see if I can work that into my program.
In the above line of code I'm getting the name of the file(s) in a given directory, but how can I also get the permissions? This is what I want to see.
-rwxr-xr-x 1 garrett garrett 158 Nov 23 10:49 dirlist.py
drwxr-xr-x 2 garrett garrett 4096 Nov 23 10:32 test.dir
-rw-r--r-- 1 garrett garrett 0 Nov 23 10:32 test.txt
In the above code how can I call all the command line arguments with the prin_params function without having to code input1, input2, input3, etc... When I'm doing testing liket this I would like to be able to just feed my command line arguments right inow print_params() intread of having to manually code every line. I tried print_params(sys.argv[]) but it did not work
When I run: ---mysql> SET PASSWORD FOR 'garrett'@'localhost' = PASSWORD('abc123'); I get: ---ERROR 1133 (42000): Can't find any matching row in the user table
Also, when I run: ---mysql> UPDATE mysql.user SET Password=PASSWORD('abc123') WHERE User='garrett' AND Host='localhost';
I just purchased a new ASUS desktop with a 1TB HD loaded with Window$ 8. I plugged in my two linux drives (OS & home DIR) but the screen was black and nothing would show up, I removed them again and now Windows is starting up again. Any ideas?
In the above link I see two different JS areas, Javascript function to restrict length of user input, & Javascript code. All I'm trying to do is validate that the users password of choice is at least x characters in length. Which one of these examples is what I'm looking for? Thanks.
But userEmail and userPsswd or quried from a database and checked against the email and psswd form variables. How does your version know what the email and password from the database is?
In the following program can someone please tell me why my script is skipping the first else clause and never printing "You have already changed your password"? Everything else is working fine but when I enter in a username and password that have already been entered into the system it skips the portiong of code designed for that case. Thanks.
<?php
$email = $_POST['email'];
$psswd = $_POST['psswd'];
$db = new SQLite3('./users.db', SQLITE3_OPEN_READWRITE);
if(!$db)
{
echo "Could not open/access DB";
}
else
{
$userEmail = $db->query("SELECT email FROM users WHERE email='$email'");
$userPsswd = $db->query("SELECT password FROM users WHERE email='$email'");
if($email == $userEmail && $psswd == $userPsswd)
{
echo "You have already changed your password";
}
else
{
$file = fopen("./accounts.txt", 'r+') or die("Failed to open file");
while(!feof($file))
{
$line = fgets($file);
if(strpos($line, "$email") !== false)
{
echo "User was a match";
if(strpos($line, "$psswd") !== false)
{
header("location: /ET/password/changepassword.html");
break;
}
else
{
echo "Invalid password";
break;
}
}
else
{
echo "Invalid email address";
break;
}
}
}
fclose($file);
}
?>
In the following program the first strpos() function is working just just fine when searching for a matching email address in the text file as long as it's on the first line but the second entry it jumps streight to the else clause and echos "Unknown user name" even though that email is on line to of the file. Any ideas?
<?php
$email = $_POST['email'];
$psswd = $_POST['psswd'];
echo "The email address is $email<br>";
echo "The password is $psswd<br><br>";
$file = fopen("./accounts.txt", 'r+') or die("Failed to open file");
while(!feof($file))
{
$line = fgets($file);
if(strpos($line, "$email") !== false)
{
echo "There was a match";
if(strpos($line, "$psswd") !== false)
{
echo "<br>Password is a match.";
$db = new SQLite3('./users.db', SQLITE3_OPEN_READWRITE);
if(!$db)
{
echo "Could not open/access DB";
}
else
{
echo "<br>DB is good!";
}
break;
}
else
{
echo "<br>Invalid Password!";
}
}
else
{
echo "Unknown user name";
//header("localhost/ET/password/:unknown.html");
break;
}
//echo "$line<br>";
}
//$line = fgets(preg_match($email, '$file'));
fclose($file);
?>
My program is stepping through the file line by line correctly, what I can't seem to be able to do is determine if the string supplied by the '$email' variable is a substring in the current line being processed.
(Linux) In the following program I'm trying to process the file accounts.txt line by line searching for a match to the form supplied variable '$email'. The function fgets() is stepping though the file line by line correctly but my attempts at using preg_match() and or strpos() to determine if that line contains the string contained in '$email' have failed. Any ideas or suggestions? Thanks.
<?php
$email = $_POST['email'];
$psswd = $_POST['psswd'];
echo "The email address is $email<br>";
echo "The password is $psswd<br><br>";
$file = fopen("./accounts.txt", 'r+') or die("Failed to open file");
while(!feof($file))
{
$line = fgets($file);
if(preg_match($email, $line))
{
echo "There was a match";
}
else
{
echo "There was not match";
}
//echo "$line<br>";
}
//$line = fgets(preg_match($email, '$file'));
fclose($file);
?>
(Linux) In the following code all I'm trying to do is open a file but evertime I run this script the fopen function jumps right to the die() function. Any ideas? The file accounts.txt does exist in the same directory, and I also tried refrencing the file via ./accounts.txt .
<?php
$email = $_POST['email'];
$psswd = $_POST['psswd'];
echo "The email address is $email<br>";
echo "The password is $psswd<br>";
$file = fopen("accounts.txt", 'r+') or die("Failed to open file");
?>
And now I'm getting this in the error log when I enter the name Bailey to be written into the fName field. The column name is
[Tue Sep 10 13:36:35 2013] [error] [client 127.0.0.1] PHP Warning: SQLite3::exec(): no such column: Bailey in /var/www/ET/insert.php on line 21, referer: http://localhost/ET/
In the following code the Submit button actualy says "Submit Query" on my page but I can not find anywhere that I have written "Submit Query" in the file. Any ideas? I would like to change the second one.
-> [Tue Sep 10 10:42:46 2013] [error] [client 127.0.0.1] PHP Warning: SQLite3::exec(): unable to open database file in /var/www/ET/insert.php on line 21, referer: http://localhost/ET/
I changed the owner of the DB file (et.sqlite3) to www-data and now this is what I'm getting. Before I changed the owner I was getting an "unable to write to DB" error. Code is below, any ideas? Thanks.
<?php
echo "<html>";
echo "<head>";
echo "</head>";
echo "<body>";
$db = new SQLite3('./et.sqlite3', SQLITE3_OPEN_READWRITE);
if(!$db)
{
echo "Could not open/access DB";
}
else
{
// get variable from html form
$fName = $_POST['fname'];
$lName = $_POST['lname'];
$email = $_POST['email'];
$db->exec("INSERT INTO customers VALUES('$fName', '$lName', '$email')");
}
echo "</body>";
echo "</html>";
?>
In the following small c++ program I'm trying to add '0' (zero characters) until the number of characters in the users input can be evenly divided by 3. I'v got it working except that it doesn't work when only on character is feed to the program.
input -> 123 -> nothing to change, good input -> 1234 -> becomes "001234", good input -> 12345 -> becomes "012345", good input -> 12 -> becomes "012", good input -> 1 -> get continues prompt, bad input -> 5 -> get continues prompt, bad
Any idea on why this is happening?
#include<stdio.h>
#include<stdlib.h>
#include<iostream>
#include<string.h>
int main(int argc, char *argv[])
{
char string[13] = "";
strcpy(string, argv[1]);
while(strlen(string) % 3 != 0 || strlen(string) < 3)
{
int position = strlen(string);
for(int i = 0; i < strlen(string); i++)
{
string[position + 1] = string[position];
position--;
}
string[0] = '0';
}
int groups = strlen(string) / 3;
std::cout << string << std::endl;
std::cout << groups << std::endl;
return 0;
}
IIM thanks, your suggestion, it sort of worked but I want it to display all the columns in order in one line without all the technical mumbo jumbo '=>', just simply, I want it to print out "Fisrtname, LastName, EmailAddress"
I have a very small sqlite3 database with one row consisting of three columns but I can get the page to display the row to save my life. So far all I've been able to get the page to display is the first column of the one row that's in my DB using querySingle and echo $result. $entry doesn't seem to be doing anything neither does the bottomw while loop. Any ideas. All I want to do here is display the one row that's in my DB to the screen.
<?php
echo "<html>";
echo "<body>";
// get variable from html form
//$fName = $_POST['fname'];
//$lName = $_POST['lname'];
//$address = $_POST['email'];
$db = new SQLite3('./et.sqlite3', SQLITE3_OPEN_READWRITE);
if(!$db)
{
echo "Could not open/access DB";
}
else
{
echo "Database is here";
//$result = $db->query('select * from customers');
//var_dump($db->querySingle('select * from customers'));
//print_r($db->querySingle('select * from customers', true));
$result = $db->querySingle('select * from customers');
echo $result;
$query = sqlite_query($db, 'select * from customers');
while($entry = sqlite_fetch_array($query, SQLITE_NUM))
{
echo $entry[0]." ".echo $entry[1]." ". echo $entry[2];
}
$i = 0;
while($i < strlen($result))
{
echo $result[$i];
$i++;
}
}
echo "</body>";
echo "</html>";
?>
I can not get a page to load from the following php program. When I load the page in the browser all I get is a blank white page. I also looked in the /var/log/apache2/error.log file and found this line -> [Sun Aug 25 21:36:37 2013] [error] [client 127.0.0.1] PHP Fatal error: Call to undefined function sqlite_open() in /var/www/ET/process.php on line 9
Here's my code.
<?php
echo "<html>";
echo "<body>";
// get variable from html form
//$fName = $_POST['fname'];
//$lName = $_POST['lname'];
//$address = $_POST['email'];
$db = sqlite_open('./et', 0666, "$error_message");
//if($db == sqlite_open('./et'))
//{
//$result = sqlite_query($db, 'select * from customers');
//echo $result;
//}
echo "hello world!";
echo "</body>";
echo "</html>";
?>
