divyakrishnan 20 Junior Poster

please suggest any sample script.

divyakrishnan 20 Junior Poster

Hi,
I want to upload files from one remote server to another using CURL

I used following to upload a text file in "localhost/uploads/example.txt" to another machine http://192.168.0.202/example/

<?php


$ch = curl_init();

$data = array('name' => 'Foo', 'file' => '@localhost/uploads/example.txt');

curl_setopt($ch, CURLOPT_URL, 'http://192.168.0.202/example/');
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $data);

curl_exec($ch);
?>

The code is not working.

divyakrishnan 20 Junior Poster

How to disable close button of a pop up window using javascript?

divyakrishnan 20 Junior Poster

Hi..
I am using tinymce editor for mathematical and graphical functions.
The graph in editor content which is inserted into the database is not showing in firefox and chrome.
But it can be viewed in Explorer.

I have downloded script from
http://www.imathas.com/editordemo/demo.html

There is demo is provided in the above link.
The demo has also the same problem.
After submitting the content(with graph) it will not shown in
http://www.imathas.com/editordemo/output.php

divyakrishnan 20 Junior Poster

Hi...

Is there any PHP rich text editor with mathematical functions?

divyakrishnan 20 Junior Poster

Use

<?php 
session_start();
session_destroy();
?>
for clearing all sessions
divyakrishnan 20 Junior Poster

Try following example

image_ajax.php

<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title></head>

<body>
<script type="text/javascript" src="jquery-1.3.1.min.js"></script>

<script type="text/javascript">
function get1()
{   

alert('inside fun');

        var dgroup=$("#int_entry_id").val();
        alert(dgroup);


        $.post("test1.php",{dval:dgroup},function(data)
        {
            alert("ajax_loaded");

            //alert("data="+data);
            var image = new Image();
image.onload = function(){
    document.body.appendChild(image);
};
image.src = data;




        });


}
</script>



<form name="f">

<select name="int_entry_id" onChange="get1()" id="int_entry_id"  >
<option value=""  selected="selected">Select One</option>
<option value="1">1</option>
<option value="2">2</option>
</select>

</form>
<p id="img"></p>
</body>
</html>

test1.php

<?php

$group=$_POST['dval'];
if($group==1)
echo "p2.jpg";
if($group==2)
echo "p1.jpg";
?>
divyakrishnan 20 Junior Poster

Redirect to another page other than header("Location:http://bannistermarketinggroup.co.uk/site_optimization/");
Write down the thank u message and use a button or hyper link to redirect to header("Location:http://bannistermarketinggroup.co.uk/site_optimization/"); page.Or use a timer to redirect to header("Location:http://bannistermarketinggroup.co.uk/site_optimization/"); after printing message.

divyakrishnan 20 Junior Poster

I have tried it with 1.7.2 and other versions.but not working

divyakrishnan 20 Junior Poster

Not entering into the jquery post.
Not printing "ajax_loaded" and other outputs.

divyakrishnan 20 Junior Poster

Firefox version is 12.0,my JQuery version jquery-1.3.1-min.js

divyakrishnan 20 Junior Poster

Hi,
I have used the following code to load data from a php page using AJAX with JQuery.The script running well in all browsers except Firefox.
The script I used is as follows.
test_ajax.php

<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title></head>

<body>
<script type="text/javascript" src="jquery-1.3.1.min.js"></script>

<script type="text/javascript">
function get1()
{   

alert('inside fun');

        var dgroup=$("#int_entry_id").val();
        alert(dgroup);


        $.post("test1.php",{dval:dgroup},function(data)
        {
            alert("ajax_loaded");

            alert("data="+data);


        });


}
</script>



<form name="f">

<select name="int_entry_id" onchange="get1()" id="int_entry_id"  >
<option value=""  selected="selected">Select One</option>
<option value="1">1</option>
<option value="2">2</option>
</select>

</form>
</body>
</html>

test1.php

<?php

$group=$_POST['dgroup'];
echo "Inside php";
?>
divyakrishnan 20 Junior Poster

I have tried to connect to ftp server it windows. It works well with. But when I used the same with red hat i was unable to connect to server.
ftp service is already running in redhat.

 $con_id=ftp_connect("192.168.0.8")or die("Couldn't connect to"); ;

 $login_result = ftp_login($con_id, "newuser", "wampp");
// check connection
if ((!$con_id) || (!$login_result)) {


       echo "connection has failed!";

   } else {
       echo "Connected to $ftp_server, for user ".".....";
   }
divyakrishnan 20 Junior Poster

I want to count files from a directory which is stored in a remote server .
I used the following code . But obtained warning

<?php
$url='192.168.0.138/img/12/12N69/';
$dir = opendir($url);

//List files in images directory
while (($file = readdir($dir)) !== false)
  {

  echo "filename: " . $file . "<br />";
  }
closedir($dir); 
?>

Warning:
Warning: opendir(http://192.168.0.138/img/12/12N69/) [function.opendir]: failed to open dir: not implemented in C:\xampp\htdocs\divya\remote_files\remote.php on line 3

Warning: readdir() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\divya\remote_files\remote.php on line 6
filename:

divyakrishnan 20 Junior Poster

How to count number of files in a directory from a remote server using curl?

divyakrishnan 20 Junior Poster

I used the code given below to take the count of files in a folder which is in another machine. On my localhost the glob() is working fine, BUT on the server it displays the array size as 0.

$dir_path ="http://192.168.0.202/img/$sub_code/$sub_code".N."$churunano/*.jpg*";
$count = count(glob($dir_path));



How to find the count of the files?
divyakrishnan 20 Junior Poster

Sorry Its my code mistake.Actually the code is

    <?php


        > if(isset($_POST['st']))
        > {
        > while ($item = current($_POST))
        > {
          $key=key($_POST);
        > echo $_POST[$key];
        > next($_POST);
        > }
        > }
        > ?>

Thanks for help

divyakrishnan 20 Junior Poster

Hi...

I want to display associative using variable as its key value.
I used the following script.
But it is not functioning.

<body>
<?php
if(isset($_POST['st']))
{
while ($item = current($_POST)) 
{

        echo $_POST[$key];

    next($_POST);
}
}
?>
<form id="form1" name="form1" method="post" action="mysql_inj.php">
  <p>
    <label for="textfield"></label>
    <input type="text" name="t1" id="textfield" />
  </p>
  <p>
    <input type="text" name="t2" id="textfield2" />
  </p>
  <input type="submit" name="st" id="textfield3" />
</form>
</body>
</html>
divyakrishnan 20 Junior Poster

Is their any way to count the files in network share?

The "img" folder in 192.168.0.138 is shared.

divyakrishnan 20 Junior Poster

Hi..
How to count no of files in a directory which is in another machine?
I used the following code.But it is not working.

<?php
 $dir_path ="file://192.168.0.138/img/$sub_code/$sub_code".N."$churunano/*.*";
  $count = count(glob($dir_path));
     $files = glob($dir_path);
     ?>



 The above code returns the count as 0.
divyakrishnan 20 Junior Poster

I have already completed the application.
Is it possible to hide url without changing url path in my php code.

divyakrishnan 20 Junior Poster

Hi..
I want to hide/rewrite the URL of my php project.
I found many forums regarding this.
I have a doubt in .htaccess file.
Is it need to create a new .htaccess inside my project folder ?

divyakrishnan 20 Junior Poster

Thank u.Its working

divyakrishnan 20 Junior Poster

I have a shared folder with images in a machine. How can I display images from that machine in a web page in another machine. I used the follwing code but obtained no output

** <?php $img_src="file://192.168.0.138/E:/img1/12/12N69/12N69$0001A1.JPG"; ?>
<img src="<?php echo $img_src ?>" alt="" width="1000" height="220" id="myimg" />**

divyakrishnan 20 Junior Poster

Is it possible to open the e-book in client machine's flashplayer without downloading ?

divyakrishnan 20 Junior Poster

I want to open an e-book which is stored on server in exe format. Client want to open and view the e-book without downloading in the client machine.

divyakrishnan 20 Junior Poster

I can run the exe from server side using PHP.But on client machine I can't run the exe.

divyakrishnan 20 Junior Poster

Is it possible to run an exe file which is saved on server machine using exec() function?
I

divyakrishnan 20 Junior Poster

Hi..

Anyone please help me to find the duration between two date-times in following format?

format is
Date1="23-03-2012 04:25PM"
Date2="26-09-2013 08:26AM"

I want to find out the diffence between Date1 and Date2 in following format.

The Result ="no of Years:no of Days:no of Hours:no of Mintues:no of Seconds"

divyakrishnan 20 Junior Poster

Hi...
I want a to print a receipt using dot matrix printer such that the paper should not eject fully out from printer after printing. Any idea ?

divyakrishnan 20 Junior Poster

You can refresh the page by using meta tag

<meta http-equiv="refresh" content="5; url=home.html">

This will refresh the current page after 5 seconds and will load home.html

divyakrishnan 20 Junior Poster

Use for loop to access tables.

for($i=1;$i<=12;$i++)
  {

$q="SELECT * FROM table".$i;
/*
Do ur table processing
*/

}
divyakrishnan 20 Junior Poster

This means that your user account does not have the necessary privileges to create a database.Contact the administrator.Try to create the database using phpMyadmin or SQL YOG.

divyakrishnan 20 Junior Poster

Use the PHP delimiters before starting HTML tags.Change your code as to

<?php
 if ($_POST["page"] == "confirm")
 {
   confirmPage ();
 }
 else
 {
    orderForm();
 }

 function orderForm()
 {
  $script = $_SERVER['PHP_SELF'];
    ?>
	  <html>
  <head>
  <title> Online Sign Up </title>
  </head>
  <body>
  <h3> Online Sign Up</h3>
  <form method = "post" action = "$script">
    <p>
    <table border = "2" width="400">
    <th>Time</th>
    <th>Name</th>

<?php
    $schedule = getSchedule();
    for($i = 0; $i<count($schedule); $i+=2)
    {
        $index = $i+1;
        print("<tr>");
        print("<td> <center> $schedule[$i] </center> </td>");
        if($schedule[$index]=="")
        {
            print("<td> <center> <input type = \"text\" name = \"$index\" size = \"30\"> </center> </td>");
        }
        else
        {
            print("<td> <center> $schedule[$index] </center> </td>");
        }
        print("</tr>");
    }
 ?>
  </table>
  <input type = "hidden" name = "page" value = "confirm" />
  </p>
  <p>
  <input type = "submit" value = "Submit" />
  </p>
  </form>
  </body>
  </html>
<?php
  }

  function getSchedule()
  {
    $lines = file("./signup.txt", FILE_IGNORE_NEW_LINES);
  $schedule = array();
  foreach ($lines as $line_num => $line)
  {
    $schedule[$line_num] = $line;
  }
  return $schedule;
  }

  function setSchedule($schedule)
  {
    $file = fopen ("./signup.txt", w);
    for($i=0; $i<count($schedule); $i++)
    {
        fwrite($file, $schedule[$i]."\n");
    }
    fclose($file);
  }

  function confirmPage()
  {
    $script = $_SERVER['PHP_SELF'];
    $schedule = getSchedule();
   ?>
    <html>
    <head>
    <title> Sign Up </title>
    </head>
    <body>
    <h2> Confirmation </h2>
    <p>
<?php
    for($i=1; $i<=count($schedule); $i+=2)
    {
        if($_POST[$i])
        {
            if($schedule[$i] == "")
            {
                $index = $i-1;
                $schedule[$i] = $_POST[$i];
                print("$schedule[$i] is now scheduled for $schedule[$index] \n");
            }
            else
            {
               
               echo " Unable to add $schedule[$i] to $schedule[$index]. Please enter another time.";
			   ?>
                <form>
                <input type = "hidden" name = "page" value = "" /> …
divyakrishnan 20 Junior Poster

Try this code

<body>
<form id="form1" name="form1" method="post" action="display.php">
  <table width="200" border="1">
    <tr>
      <td>Name</td>
      <td><input name="t1" type="text" id="t1" /></td>
    </tr>
    <tr>
      <td colspan="2"><div align="center">
        <input type="submit" name="Submit" value="Submit" />
      </div></td>
    </tr>
  </table>
</form>
</body>

display.php

<?php
$name=$_REQUEST['t1'];
echo $name;
?>
divyakrishnan 20 Junior Poster

Use AJAX technologies.
It helps u to call a php page from javascript.
Also u can pass the values from javascript to php.

divyakrishnan 20 Junior Poster

Hi...
I want to move an uploaded file to another machine.I had given the file path to move_uploded_file() function including IP address .The folder is a shared folder.My code shown below.

<?php
if ($_FILES["file"]["error"] > 0)
  {
  echo "Error: " . $_FILES["file"]["error"] . "<br />";
  }
else
  {
  echo "Upload: " . $_FILES["file"]["name"] . "<br />";
  echo "Type: " . $_FILES["file"]["type"] . "<br />";
  echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
   move_uploaded_file($_FILES["file"]["tmp_name"],"192.168.0.23/E:/pdf/" . $_FILES["file"]["name"]);


  echo "Stored in: " . "upload/" . $_FILES["file"]["name"];

  }
?>

I am getting the error like as

Warning: move_uploaded_file() [function.move-uploaded-file]: Unable to access 192.168.0.23/E:/pdf/Picture 240.jpg in C:\xampp\htdocs\divya\fileupload\upload_file.php on line 11

divyakrishnan 20 Junior Poster
divyakrishnan 20 Junior Poster

Check out the spelling of kategori and id'.It should be match with table field name.

divyakrishnan 20 Junior Poster
divyakrishnan 20 Junior Poster

It is difficult to extract the address into three components.Because all the words are separated by space character.There is no other character is for string extraction.
Add , to your address like 252 westend drive, Sommerset west, 0185 before insertion.
Then split the string into array elements using explode() function.

divyakrishnan 20 Junior Poster

I suppose you are misspelled the form fields "kategori","id".
Check out your previous page for correct spelling.

It is clear , if you post the previous page code.

divyakrishnan 20 Junior Poster

Try to execute the exe of apache & mysql.
Go to "C:\wamp\bin\apache\Apache2.2.17\bin" ,then run "httpd.exe" and go to "C:\wamp\bin\mysql\mysql5.5.8\bin\" run "mysql.exe" .

divyakrishnan 20 Junior Poster

There is an error in your query .
So the mysql_query function returns a boolean, and not a resource.
mysql_fetch_array() cannot works with a boolean value.
You can check the error in mysql query by using following code

$result = mysql_query("SELECT * FROM event");
if ($result != false) {
    // use $result
} else {
    // an error has occured
    echo mysql_error();
    die;    // note : echoing the error message and dying 
            // is OK while developping, but not in production !
}
divyakrishnan 20 Junior Poster

Print all your query statements and execute it using phpmyadmin(or any mysql browser).

divyakrishnan 20 Junior Poster
divyakrishnan 20 Junior Poster

Submit your form and retrieve the check box value as

$store_id=$_REQUEST['store_id'];
divyakrishnan 20 Junior Poster

Change is as

}
}</form>
?>
</body></html>

to

}
	}
?>
</form>
</body></html>
divyakrishnan 20 Junior Poster

Where r u calling class functions?Can you post entire code?

divyakrishnan 20 Junior Poster

Change the code

$arr=unserialize($_REQUEST['pname']);

to

$arr=unserialize(clean_slweg($_REQUEST['pname']));