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Hi Every body
Is my answer correct for this question -
Obtain the minimal form for the following Boolean expression using Karnaugh map.
F(U, V, W, Z) = ∑(0, 1, 2, 3, 6, 7, 8, 9, 10, 13, 15)

My answer -
a48a42f649b78dce10e6abdea215d087

There are four pairs and one quad that reduce as given below:
Pair-1(m7 + m6) reduces to U’VW
Pair-2(m8 + m9) reduces to UV’W’
Pair-3(m13 + m15) reduces to UVZ
Pair-4(m8 + m10) reduces to UV’Z’
Quad (m0 + m1 + m2 + m3) reduces to U’V’
Simplified Boolean expression for given K-map is F(U,V,W,Z) = U’VW + A’C’O + UVZ + UV’Z’ + U’V’

But my teacher said I am wrong according to her

answer is not matching with the rules of boolean..as it wants first quads and then pair but answer is showing diff.

Guide me

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Last Post by ravikash123
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Hi vishalonne,

you able to make a one more group of 4 elements(all 4 corner elements) due to this u can get more exact result..

Regards..
Ravikash

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