Hi Every body
Is my answer correct for this question -
Obtain the minimal form for the following Boolean expression using Karnaugh map.
F(U, V, W, Z) = ∑(0, 1, 2, 3, 6, 7, 8, 9, 10, 13, 15)

My answer -
a48a42f649b78dce10e6abdea215d087

There are four pairs and one quad that reduce as given below:
Pair-1(m7 + m6) reduces to U’VW
Pair-2(m8 + m9) reduces to UV’W’
Pair-3(m13 + m15) reduces to UVZ
Pair-4(m8 + m10) reduces to UV’Z’
Quad (m0 + m1 + m2 + m3) reduces to U’V’
Simplified Boolean expression for given K-map is F(U,V,W,Z) = U’VW + A’C’O + UVZ + UV’Z’ + U’V’

But my teacher said I am wrong according to her

answer is not matching with the rules of boolean..as it wants first quads and then pair but answer is showing diff.

Guide me

Hi vishalonne,

you able to make a one more group of 4 elements(all 4 corner elements) due to this u can get more exact result..

Regards..
Ravikash