the following should return 1 row

$search= "Timothy";

$query4 = mysql_query("SELECT * FROM test1, test2, combination WHERE test1.IDONE = `combination`.IDONE AND test2.IDTWO = combination.IDTWO AND test1.NAME LIKE '%$search%'",$this->connect) or die(mysql_error());

instead it returns zero.

the query should take values from all three tables according to the where clause.

in short to describe the table structure.

3 tables(test1, test2, combination)

test1 has primary key IDONE, test2 has primary key IDTWO

combination looks like this

CREATE TABLE `combination` (
IDONE int(8) NOT NULL,
IDTWO varchar(11) NOT NULL,
INFO char(200) NOT NULL,

INDEX (IDONE, IDTWO),
PRIMARY KEY (IDONE,IDTWO),
FOREIGN KEY (IDTWO) REFERENCES `test2` (IDTWO)  ON UPDATE CASCADE ON DELETE CASCADE,
FOREIGN KEY (IDONE) REFERENCES `test1` (IDONE) ON UPDATE CASCADE ON DELETE CASCADE
) ENGINE=INNODB;

i havent done the relational database wrong.. there is no mysql_errors either. any idea?

I don't see any errors in the structure, so presumably it's in the data. Please show them.

Are you sure about these quotes around combination? I've never done that when using sql.

WHERE test1.IDONE = `combination`.IDONE

@drjohn. Those back quotes around table or column names are legal (and often a good idea). I tend not to do it that way because I'm a lazy typist. I'd have written

"SELECT * FROM test1 as t1, test2 as t2, combination as c WHERE t1.IDONE = c.IDONE AND t2.IDTWO = c.IDTWO AND t1.NAME LIKE '%$search%'"

add:
In fact, I'd use an explicit join:

"SELECT * FROM test1 as t1 join test2 as t2 join combination as c on t1.IDONE = c.IDONE AND t2.IDTWO = c.IDTWO where t1.NAME LIKE '%$search%'"