Ok. So. Who doesn't know how to convert on paper or in their head decimal numbers ==» binary number, or vise-versa? Well. I've successfully programmed a conversion calculator for those who just never took the time to learn, for those who don't care to learn, and for those who've got a hard time doing the conversions on paper or in their head. Basically, when you select option 1 you can type in a number and convert it from a decimal number into a binary. And when you select option 2, you do the opposite. This little program comes in handy when you need to know, or just want to know what the equivalent number, whether it be binary or decimal. Here is an example of a decimal number:

217

Here is it's binary equivalent:

11011001

Please comment on this, and let me know what you guys think of it. Thanks!

# -*- coding: cp1252 -*-
import sys, os, time

#This is where you convert a binary number into a decimal number.
def binaryToDecimal():
    os.system('cls')
    while True:
        print "To go back to the main menu type 'e' and press enter"
        print
        print "Binary numbers consist of only '1's and '0's "
        binary = raw_input('Type in the binary number: ')
        if binary == "e":
            mainmenu()
        else:
            binarylist = list(binary)
            no = len(binarylist)
            no = no -1
            diginum = 0
            i = 0
            while no > -1:
                if binarylist[no] == '1':
                    kj = 2**i
                    diginum = diginum + kj
                no = no -1
                i = i +1 
            print diginum
            raw_input()

#This is where you convert a decimal number into a binary number.
def decimalToBinary():
    os.system('cls')
    try:
        while True:    
            print "To go back to the main menu type 'e' and press enter" 
            print
            number = raw_input('Type in the digital number: ')
            if number == "e":
                mainmenu()
            else:
                number = int(number)
                aaa = str(number)
                i = 0
                numlist = []
                while number != 0:
                    numlist.append(number)
                    number = number/2 
                    i = i + 1
                binarynum = []
                i = i-1
                while i !=-1:
                    bd = str(numlist[i])
                    bdl = list(bd)
                    bdn = len(bdl)
                    bdn = bdn - 1
                    bx = bdl[bdn]
                    if bx == '0' or bx == '2' or bx == '4' or bx == '6' or bx == '8':
                        binarynum.append('0')
                    if bx == '1' or bx == '3' or bx == '5' or bx == '7' or bx == '9':
                        binarynum.append('1')
                    i = i - 1
                print ''.join(binarynum)
                raw_input()
    except ValueError:
        print "The input should only numbers"
        digitalToBinary()
        raw_input()

#This is the credits function....
def credit():
    os.system('cls')
    text = """###########################
Author: Christopher "Kipp" Moore
Date  : 12/09/2009
Vision: Binary Conversions v1.0
###########################
    """
    for character in text:
        sys.stdout.write(character);sys.stdout.flush(),time.sleep(.03),
    raw_input()

#Here is the main menu....
def mainmenu():
    while True:
        os.system('cls')
        menu = """##############################
#     What Do You Want To Do?                  #
#                                                                         #
#1) Convert Decimal ==» Binary                  #
#2) Convert Binary ==» Decimal                 #
#3) Credits                                                       #
#4) Exit Program                                            #
##############################

Choice [1-4] : """
        choice = raw_input(menu)
        if choice == "1":
            decimalToBinary()
        if choice == "2":
            binaryToDecimal()
        if choice == "3":
            credit()
        if choice == "4":
            print "Good-bye! Thanks for using the converter!"
            return

mainmenu()

Just a note, there is related Python snippet at:
http://www.daniweb.com/code/snippet216539.html

Also Python has a few built-in functions to offer ...

# with Python2 you can convert a
# binary (base 2) string to a denary (base 10) integer
print( int('11111111', 2) )  # --> 255

# Python3 adds the function bin() to convert a
# denary integer (base 10)) to a binary (base 2) object
print( bin(255) )            # --> 0b11111111

# convert back again (Python3 only)
print( int(0b11111111) )     # --> 255

]

Edited 7 Years Ago by vegaseat: n/a

Thanks for that, vegaseat. Now I know, I wasn't too sure if it was posted on here or not, so I posted it anyways. ;) And, also, thanks for that code snippet you posted as well.