## wollacott

Input an integer containing only 0’s and 1’s( ie. “binary” integer) and print its decimal equivalent. {hint: use the remainder and division operators to pick off the binary numbers digits one at a time from right to left. Just as in the decimal number system, in which the right most digit has a positional value of 1, and the next digit has a positional value of 10, then 100, then 1000, and so on, in the binary number system the rightmost digit has a positional value of 1, the next digit left has a positional value of 2, then 4, then 8, and so on. Thus the decimal number 234 can be interpreted as 4*1+3*10+2*100. The decimal equivalent of binary 1101 is 1*1+0*2+1*4+1*8 or 1+0+4+8 or 13.}

#include <stdio.h>
int bin;
int dec = 0;
scanf("%d",& bin);
int pos = 1;
while (bin) {
int digit = bin % 10;
dec += digit * pos;
bin /= 10;
pos *= 2;
}
printf("%d", dec);

## Duoas 1,025

Your code works fine for me. What's giving you trouble?

Use bin%2 bin/2

## ithelp 757

Use bin%2 bin/2, you have got binary numbers

## Duoas 1,025

Did you read the OP's post?

Your code works fine for me.

Perhaps you think you are a lot brighter than I, who took the time to actually compile and execute his code, after reading it over and finding no obvious flaw?

I'm sorry to be harsh...

## wollacott

what are code tags?

## Duoas 1,025

At the top of the forum there's an announcement post named "Please use BB Code and Inlinecode tags". It makes reading and copying code both easy and pleasant.

So, did you get your program to work?