Multiple Precision Arithmetic

[matt999tye]

I keep getting operand size conflict errors when I run this program I cant seem to get it right!

Write an assembly language program that will use multiple precision arithmetic to add the following defined word (dw) numbers in defined 16-bit registers (like ax, bx, cx and dx). (hint: use immediate addressing – and don't forget to account for the carry information).

A8Eeh
6789h
CABBh
7777h

//
// Matthew Tye 101 36 654
// Multiple Precision Arithmetic with DW's
// 252A9

    
#include "stdafx.h"
#include <iostream>

using namespace std;


int main(int argc, char* argv[])
{
//  your properly formatted assembly language data here
	 unsigned short int loword = 0;
	 unsigned short int hiword = 0;
     unsigned short int ans1 = 0;
   

        __asm {
//  your syntatically correct assembly language code here
//  column alignment markers below (to guide you)
//      |       |               |
		
		sub      eax,eax			;zero out eax register
                sub      edx,edx			;zero out edx register
                mov     ax,A8EE			       ;move A8Ee into ax
		add	 ax,6789			;add 6789 to ax
		add	 ax,CABB		       ;add CABB to ax
		add	 ax,7777			;add 7777 to ax	
		adc      dx,00			          ;accumulate in dx any carries
		mov     loword,ax		       ;move ax into loword
		mov  	hiword,dx		       ;move dx into hiword



        }

    return(0);
}

[Duoas]

You have to call ADC after each ADD. (The carry flag is only one bit deep.)

Hope this helps.

[matt999tye]

You have to call ADC after each ADD. (The carry flag is only one bit deep.)

Hope this helps.

i tried this, but i am assuming i am missing something else as i get the same error

sub     eax,eax			;zero out eax register
                      sub     edx,edx	     ;zero out edx register
                      mov     ax,A8EE			;move A8Ee into ax
		add		ax,6789			;add 6789 to ax
		adc     dx,00			;accumulate in dx any carries
		add		ax,CABB			;add CABB to ax
		adc     dx,00			;accumulate in dx any carries
		add		ax,7777			;add 7777 to ax	
		adc     dx,00			;accumulate in dx any carries
		mov     loword,ax		;move ax into loword
		mov  	hiword,dx		;move dx into hiword

[Duoas]

Ah, yes, I forgot to address your question. Sorry. :$

unsigned int corresponds to EAX.
unsigned short corresponds to AX.
unsigned char corresponds to AL.

Hope this helps.