0

Hello everyone, and thank you in advance for any help you can give!

I am working on a simple program with some long integers, which I have defined as type long long, with LLU after them. I am trying to use these variable names in an arithmetic expression, but when the results print out, the number simply shows as a 0. I have tried putting simple numbers in the expression, which worked, so I was thinking that maybe it has something to do with the fact that I have LLU after my numbers. If that is the case, however, I need a new idea on how to work with this program, because I can't define those integers as anything but long long with LLU after it.

Any ideas on how to work this out?

```
#include <iostream>
using namespace std;
int main(int, char**)
{
long long n = 6647817899LLU;
long long f = 10299685494LLU;
int i = ((f - n) / n) * 100;
cout << "Part 4: " << f << " is " << i
<< "% more than " << n << endl;
system("pause");
return 0; }
```