I am working on a problem where I must show all perfect integers between 1 and 1000, as well as the divisors to get them. I can get the integers just fine with this code:

```
#include <iostream>
using namespace std;
void Perfect(int);
int main() {
for (int i = 1; i < 1000; i++) {
Perfect(i);
}
system("pause");
return 0;
}
void Perfect (int number) {
int sum = 0;
for (int i = 1; i < number; i++) {
if (number % i == 0) {
sum = sum + i;
}
}
if (sum == number) {
cout << sum << "=" << endl;
}
}
```

But I can't figure out where to put things in to get each divisor for each number. It needs to show up like this:

28 = 1 + 2 + 4 + 7 + 14

Any ideas for how to do that? Thanks