how can i convert an array of char to char?

this what i want to do

char *argv[];

char i


compare and index or argv to i.

An array of char cannot be converted to char unless it is an array of 1. The reason is that one cannot fit more than one char value into a single char variable. You can process each char individually though. To do that, use two nested loops, one for each argument string and one for the characters in each string:

#include <iostream>

int main(int argc, char *argv[])
{
  // Start at 1 to skip the program name
  for (int i = 1; i < argc; ++i) {
    for (int j = 0; argv[i][j] != '\0'; ++j) {
      char ch = argv[i][j];

      std::cout << ch << '\n';
    }
  }
}

i dont think i have i need to check if the checking for U command or I!!!

Ed's just guessing now, but are you trying to parse command line options? Something like this?

#include <iostream>
#include <stdexcept>

// Notes:
//   Accepted commands
//     -I <single arg>
//     -U <single arg>
//
//  example: myprog -I woohoo -U "Ed rules!"

int main(int argc, char *argv[]) try
{
  // Start at 1 to skip the program name
  for (int i = 1; i < argc; ++i) {
    // Only options are allowed
    // Options consist of - and at least one more character
    if (argv[i][0] != '-' || argv[i][1] == '\0')
      throw std::runtime_error("Bad format");

    // Handle the option
    switch (argv[i][1]) {
      case 'I':
        // Be sure to skip the option's argument
        std::cout << "Reading I: " << argv[++i] << '\n';
        break;
      case 'U':
        // Be sure to skip the option's argument
        std::cout << "Reading U: " << argv[++i] << '\n';
        break;
    }
  }
}
catch (const std::exception& ex) {
  std::cerr << ex.what() << '\n';
}
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