Member Avatar for daviddoria

I ran this:

cout << "has nan q?" << numeric_limits<int>::has_quiet_NaN << endl;
	cout << "has nan s?" << numeric_limits<int>::has_signaling_NaN << endl;
	cout << "has nan q?" << numeric_limits<double>::has_quiet_NaN << endl;
	cout << "has nan s?" << numeric_limits<double>::has_signaling_NaN << endl;

and I get
0
0
1
1

why would int not have NaN?? I'm using g++.

Thanks!

Dave

  • 2 Contributors
  • 1 Reply
  • 168 Views
  • 6 Hours Discussion Span
  • Latest Post Latest Post by Salem
Member Avatar for Salem

The standard doesn't rule out the possibility that integers can have traps like NaN's, it's just that your implementation doesn't have them.

Be a part of the DaniWeb community

We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.