Can any body explain me about overloading concept of () operator?
I need to know why do we need to overlload () operator and how do we achieve that?
Thanks in Advance
>So is the conversion operator not considered overloading the () operator whereas the >function call operator is considered overloading the () operator, both are considered >overloading the () operator, or neither are considered overloading the () operator? The function call operator and [ICODE]operator()[/ICODE] are the same thing. Here's how you … Read More