def P(p_0, t, i):
return p_0 * (1+i)**t
when i call the fuction P(1000,7,5) it returns it as 1000 and any otha number i put as p_0 it returns that number and i cant figure out why
bman923
0
Newbie Poster
Recommended Answers
Jump to Posthm, I tried this on the python console
>>> def P(p_0, t, i): ... return p_0 *(1+i) ** t ... >>> P(10000, 5, 7) 327680000 >>> P(10000, 7, 5) 2799360000L >>>so I can't see your problem ?
All 2 Replies
Gribouillis
1,391
Programming Explorer
Team Colleague
hm, I tried this on the python console
>>> def P(p_0, t, i):
... return p_0 *(1+i) ** t
...
>>> P(10000, 5, 7)
327680000
>>> P(10000, 7, 5)
2799360000L
>>>so I can't see your problem ?
Chewie-DK
0
Newbie Poster
It also works for me, but maybe try
def P(p_0, t, i):
return (p_0 * (1+i)**t)
or
def P(p_0, t, i):
a= p_0 * (1+i)**t
return aAnd see if that fixes it for you.
(also could check your version of Python and get one of the newer ones if it's old)
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