If your definition of "help" equates to "do the work for me", no. Why don't you go off and try to come up with something on your own before you start begging for "help"?

If your definition of "help" equates to "do the work for me", no. Why don't you go off and try to come up with something on your own before you start begging for "help"?

As I understood, it's very simple game. It may even not be treated as a real "game".

There's a matrix of cells, and cells can be live or dead. You set up a matrix (decide which cell is live and which one is dead) and then you start the game.
Then you have nothing more to do. Game has 4 simple rules about creating new cells, destroying old ones, and by that a matrix changes all the time, and you can watch :)

Actually it can turn into a game, there a ae many different arrangements of cells in the game of life, which have different names, sch as glider -- these will move in 1 direction continually untill another live cell interupts this.

Many appterns can be created to do many differents things, there are very large patterns that have been designed to create different patterns continually.

Also from what i know the Game of Life can be researched greatly by algorithms and alot of time is spent investigating these algotihms. In actual fact the fastest way to make the largest number of cells live was found by a computer algorithm

Write a C program that should create a 10 element array of random integers (0 to 9). The program should total all of the numbers in the odd positions of the array and compare them with the total of the numbers in the even positions of the array and indicate ...

Hi. so this is actually a continuation from another question of mineHere but i was advised to start a new thread as the original question was already answered.

This is the result of previous question answered :

I have a 2d matrix with dimension (3, n) called A, I want to calculate the normalization and cross product of two arrays (b,z) (see the code please) for each column (for the first column, then the second one and so on).
the function that I created to find the ...