hi! to everyone
i have to make a program in c++ about factorial but the main problem is that the working of factorial must me shown for eg.
4!=4*3*2*1
like this on the output screen i had done upto here....

#include <stdio.h>
#include <conio.h>
int main()

{
long float i,j,n;
clrscr();

gotoxy(33,7);
printf("enetr any value=");
scanf("%lf",&n);

gotoxy(32,4);
printf("-----------WORKING--------------");
gotoxy(32,5);
printf(" =======");
j=1;


for ( i=1; i<=n; i++)
{

j=j*i ;
}

gotoxy(33,8);
printf("The factorial is %lf\n", j);

getch();
}

if any one help me in easier way because iam beginner user of c++
thank you!

My clue for you

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Edited 3 Years Ago by mike_2000_17: Fixed formatting

Hallo
first of all, I think the way u code IS NOT STANDARD C++ !!!! Instead it looks more like C to me.
Maybe it is not important for u , maybe it is for your professor :d

Here is what u wanted:

#include <iostream>
#include <iomanip>

int main () { 

	long number; // the number to use to calculate its factorial
	long factor; // the factorial of the number
	long term; // next term to use in the calculation


	// prompt and get the first number
	std::cout << "Enter a number or -1 to quit: ";
	std::cin >> number;

	while (number >= 0 && std::cin) 
	{
		// calculate number factorial 
		factor = 1; 
		for (term=2; term <= number; term++) 
		{ 
			factor *= term; 
		} 
		
		// output number and its factorial
		if(number == 1)
		{
			std::cout << number << "! = 1*1=1" <<std::endl;
		}
		else
		{
			std::cout << number << "! = " ;
			for (int k=2; k<number+1; ++k)
			{
			     std::cout<<number+2-k<<"*";
			}
			std::cout <<"1 ="<< factor <<std::endl; 
		}

		// get another number to do 
		std::cout << "Enter a number or -1 to quit: "; 
		std::cin >> number; 
	} 
	
	return 0; 
}

I leave it to u to do some improvements :)

Remove the long before the float and change %lf to %f . Then it'll work.
Also, it'd be clearer if you'd intialize j when declaring it, and not some lines after it.

And here the solution in C like u asked:

//#include <iostream>	//c++

#include <stdio.h>		//the same in C

int main () { 

	long number; // the number to use to calculate its factorial
	long factor; // the factorial of the number
	long term; // next term to use in the calculation


	// prompt and get the first number
	//std::cout << "Enter a number or -1 to quit: ";	//C++
	printf("Enter a number or -1 to quit: ");		//the same in C
	//std::cin >> number;					//C++
	scanf("%ld",&number);					//the same in C

	//while (number >= 0 && std::cin)
	while (number >= 0) 
	{
		// calculate number factorial 
		factor = 1; 
		for (term=2; term <= number; term++) 
		{ 
			factor *= term; 
		} 
		
		// output number and its factorial
		if(number == 1)
		{
			//std::cout << number << "! = 1*1=1" <<std::endl;//C++
			printf("%d!=1*1= 1\n",number);			//the same in C
		}
		else
		{
			//std::cout << number << "! = " ;		//C++
			printf("%d!=",number);				//the same in C
			for (int k=2; k<number+1; ++k)
			{
			//std::cout<<number+2-k<<"*";			//C++
			printf("%d*",number+2-k);				//the same in C
			}
			//std::cout <<"1 ="<< factor <<std::endl; 	//C++
			printf("1= %d\n",factor);				//the same in C
		}

		// get another number to do 
		//std::cout << "Enter a number or -1 to quit: ";	//C++ 
		printf("Enter a number or -1 to quit: ");		//the same in C
		//std::cin >> number; 					//C++ 
		scanf("%ld",&number);					//the same in C

	} 
	
	return 0; 
}
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