A positive integer is entered from the keyboard. If it's even, all even integers from 2 up to and includng the entered integer are displayed. If odd, all odd integers from 1 up to and including the entered integer are summed, and the sum displayed.

{Question:
A positive integer is entered from the keyboard.
If it's even, all even integers from 2 up to
and includng the entered integer are displayed.
If odd, all odd integers from 1 up to
and including the entered integer are summed,
and the sum displayed.
}
Program Program01;
Uses Crt;
{we need two variables}
Var TheNumber:Integer;{entered number}
i:Integer; {for loop}
{procedure for even}
Procedure EvenNumbers(EN01:Integer);
Begin
WriteLn(EN01,' is an even number!');
For i:=1 To EN01 Do
Begin
If (i Mod 2 = 0) Then
Write(i,' ');
End;
End;
{procedure for odd}
Procedure OddNumbers(ON01:Integer);
Begin
WriteLn(ON01,' is an odd number!');
For i:=1 To ON01 Do
Begin
If (Odd(i))Then
Write(i,' ');
End;
End;
Begin {main}
Write('Give me the positive number: ');
ReadLn(TheNumber);{catch it}
Case Odd(TheNumber) Of {analize it}
True:OddNumbers(TheNumber); {if true,call OddNumbers() procedure}
False:EvenNumbers(TheNumber); {if false then call the other one}
End;
ReadKey;
End.
{
-= Note By FlamingClaw =-
-=Odd(x)=- -=System Unit=-
Tests if the argument is an odd number.
Declaration:
function Odd(X: Longint): Boolean;
Target:Windows, Real, Protected
Remarks:True, if X is an odd number.
*** *** *** *** *** *** *** *** *** *** *** *** *** ***
-=y Mod x=-
If y Mod x = 0 Then y divisible by x without reminder
y:=5;
x:=3;
z:= y Mod x; 5 Mod 3 = 2 there is reminder
Mod always shows the remainder!
All programs created by me are written and tested in
Dev Pascal and/or Turbo Pascal 7.0
-= Created By FlamingClaw =-
-=2009.03.26=-
}

you have been contracted as a software develper to design a point of sales system, the system is to work in a way that ,if a customer purchase an item ...