I have a question on how to program my nested loops. This is the output i am supposed to have.

Enter the number you want to sum to: 8

0 = 0

0 + 1 = 1

0 + 1 + 2 = 3

0 + 1 + 2 + 3 = 6

0 + 1 + 2 + 3 + 4 = 10

0 + 1 + 2 + 3 + 4 + 5 = 15

0 + 1 + 2 + 3 + 4 + 5 + 6 = 21

0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28

0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 = 36

I understand enough to get the last line where just the number 8 if summed. However i am having a real hard time thinking of how to do the loop to get the previous ones. Any help is really appreciated. btw I looked through the code snippets and didnt find any help there.

Hello,

This is quite simple in fact. We will run one loop through 8 times for simplicity. Each loop around we will increase a single variable that will tell us where to stop. Here is our example:

#include <stdio.h>

int main() {
	int i, j, k, temp;

	/* initialize j */
	j = 0;
	/* loop 8 times */
	for (i = 0; i <= 8; i++) {
		/* reset variables */
		temp = k = 0;
		/* loop until k hits j */
		while (k <= j) {
			/* print number */
			printf("%d ", k);
			/* print plus sign except for last time */
			if (k != j)
				printf("+ ");
			/* add to our temporary variable */
			temp += k;
			/* increment k */
			k++;
		}
		/* print result */
		printf("= %d\n", temp);
		/* increment j */
		j++;
	}

	return 0;
}

- Stack Overflow

Here is my code that still doesnt give me the output that i need. I dont know how to capture the output from my screen to post on here.

#include <iostream>
using namespace std;


int main()
{

//Variables
	int number;
	int count = 0;
	int count2;
	int  sum = 0;
	char q;

	cout << "Programmed by";
	do {
	cout  <<endl << endl << "Enter the number you want to sum: ";
	cin >> number;
	
	 for (int count = 0; count <= number; count ++)
	 { for (int count2 = 0; count2 <= count; count2 ++) {
	 cout << count << " + ";
	 
	}
	cout << endl;
	 }
	
	
	
	cout << endl ;
	cout << "Do you want to do this again (y/n): ";
		cin >> q;
	}
	while (q == 'y' || q == 'Y');

	
return 0;
}

Thanks for the help i will look at that and you guys can disregard my feeble first attempt at it.

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