if it contains quote it cuts it out, then i am stuck on part when i just enter in a problemset without a quote or single quote. Then it doesn't gather numbers correctly but stores the entire string

int main()
{


    cout <<"enter the problemset and number""\n";
    //problems represents name and numbers
    string problems , probtitle;
    string xx;
    bool x=true;
    char quote;
    string str1, str2;
    string begin;
    //gather name
    if(cin.peek()=='"' || cin.peek() == '\'')
    {
        cin >>quote;
        getline(cin,problems,quote);
    }
    else
    {
            getline(cin,problems);
    }
cout<<problems;

    //gather problem numbers

    while(x==true)
    {
        if(cin.peek()=='0'||cin.peek()=='1'||cin.peek()=='2'||cin.peek()=='3'||cin.peek()=='4'||cin.peek()=='5'
||cin.peek()=='6'||cin.peek()=='7'||cin.peek()=='8'||cin.peek()=='9'||cin.peek()==','||cin.peek()=='-')
        {
            getline(cin,problems);
        }
        else
        {
            getline(cin,xx);
            if(xx.compare("\n"))
            {
            x=false;
            }
        }
    }
    cout<<problems;

Then it doesn't gather numbers correctly but stores the entire string

That's what you tell it to do with getline(cin,problems) . I can help you fix it by taking the entire line and parsing it, but I need you to describe the format of the problemset. Just showing your code isn't enough.

Why not just read a whole line with getline, then use a utility function which examines the line to see if quotes are present, and if so remove them.

All this peek() stuff is overly complicating things.

so my problem is they enter a line of code which contains the problemname which may contain quotes or not.Then have to find the numbers. Say do problems what ever numbers each seperated by a comma and finally state what problem set from. Can't have duplicate numbers and must be ordered.

That's more helpful, but a format specification would be better. Show an example of the input and output of the program and explain how the input got to the output.

so input could be
"bob"1-5,6-10,11-15,57
or
'bob' 1-6,1-7,9-10
or
bob 1-7,12-18
spaces don't matter after problemset name
output could be
do problems 1,2,3,4,5,6,7,12,13,14,15,16,17,18 of bob. from last example

most recent code:

#include <iostream>
#include <cstdlib>

using namespace std;

int main()
{


    cout <<"enter the problemset and number""\n";
    //problems represents name and numbers
    string problems , probtitle;
    string xx;
    bool x=true;
    char quote;
    string str1, str2;
    string begin;
    //gather name
    if(cin.peek()=='"' || cin.peek() == '\'')
    {
        cin >>quote;
        getline(cin,problems,quote);
    }
    else
    {
            getline(cin,problems);
    }

    //gather problem numbers

    while(x==true)
    {
        if(cin.peek()=='0'||cin.peek()=='1'||cin.peek()=='2'||cin.peek()=='3'||cin.peek()=='4'||cin.peek()=='5'||cin.peek()=='6'||cin.peek()=='7'||cin.peek()=='8'||cin.peek()=='9'||cin.peek()==','||cin.peek()=='-')
        {
            getline(cin,problems);
        }
        else
        {
            getline(cin,xx);
            if(xx.compare("\n"))
            {
            x=false;
            }
        }
    }
    cout<<problems;


int length=problems.find(',');
do{
    if(problems.find(',') != string::npos)
    {
        size_t a,b;
        a=problems.find(',');
        b=problems.find('-');


         if(problems.find('-') != string::npos&&b<a)
         {
                    str1 = problems.substr(0,problems.find('-'));
                    cout<<"from do ifif1\n"<<str1;
                    problems=problems.erase(0,problems.find('-'));
                    cout<<"from erase after first erase"<<problems;
                    str2=problems.substr(problems.find('-')+1,problems.find(','));
                    cout<<"from doifif2\n"<<str2;
                    problems=problems.erase(0,problems.find(',')+1);
                    cout<<"the problems left after erase are"<<problems;

        }
        else
        {
                    cout << "from do if else\n" ;
                    str1 = problems.substr(0,problems.find(','));
                    cout<<"from elseelseelseelse\n"<<str1;
                    problems=problems.erase(0,problems.find(',')+1);
        }

    }
    else
    {
        cout <<"No Comma\n";


        if(problems.find('-') != string::npos)
        {
                    str1 = problems.substr(0,problems.find('-'));
                    cout<<str1;
                    str2=problems.substr(problems.find('-')+1);
                    cout<<str2;
                    problems=problems.erase(0,problems.find('-')+1);
        }
        else
        {cout << "\n IF ELSE" ;
                    str1 = problems.substr(0,problems.find(','));
                    cout<<str1;
                    if(problems.find(',') != string::npos)
                    {
                    problems=problems.erase(0,problems.find(',')+1);
                    }
                    else{
                        problems="";
                    }
        }

    }
}while(problems.length()>0 );
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