Hey guys, maybe I am just worn out today, but can somebody look at my IF loop (the first one for selcting 1-3) and see where I am going wrong?
Everything else seems to be pretty good I think, but this is aggravating me to no end.
Thanks

#include <stdio.h>  // standard input output library
#include <string.h> // basic string handling library added for cAgain option

//Assigns tax value for calculations
#define DelMar 7.25
#define Encinitas 7.5
#define LaJolla 7.75

char cAgain;  //repeat variable for Y/N questions

int displayMenu()  // creates menu
{
    int choice;
    printf("Tax Calculation for $125 Purchase\n\n");
    printf("1. Del Mar \n");
    printf("2. Encinitas \n");
    printf("3. La Jolla \n");
    printf("\n\nPlease Select Store for Which to Calculate [1-3]:");

    scanf("%d",&choice);
    return choice;
}

int main()
{
YES:
{				
// Sales value for calculations
    float sales = 125.00;
    int storenum;
   

    storenum = displayMenu();
    if storenum >=1 || if storenum <=3     //While Loop to Request Input of 1,2,or 3, still working on this
    {
 	
  	switch (storenum) // simple switch which responds to corresponding menu choice with output
    {
    case 1:
//Calculates and Displays Store, Sales, Tax rate, Tax for Del Mar
        printf("\nDel Mar \tSale $%.2f\tRate %.2f%%\tTax $%.2f%\t\n\n",sales, DelMar, sales*DelMar/100); //values are correct so I am leaving it this way. ahead of schedule here.
        break;
    case 2:
//Calculates and Displays Store, Sales, Tax rate, and Tax for Encinitas
        printf("\nEncinitas \tSale $%.2f\tRate %.2f%%\tTax $%.2f%\t\n\n",sales, Encinitas, sales*Encinitas/100);
        break;
    case 3:
//Calculates and Displays Store, Sales, Tax rate, and Tax for La Jolla
        printf("\nLa Jolla \tSale $%.2f\tTax %.2f%%\tTax $%.2f%\t\n\n",sales, LaJolla, sales*LaJolla/100);
        break;
    } //Storenum switch end
    }
    else
    {
    fflush(stdin);
    	printf("\nPlease enter 1,2 or 3\n");
    	
    	printf("\n\tINVALID NUMBER ENTERED! Would you like to try again? (y/n) ");//allows repeat 
            scanf("%c", &cAgain);  //scan input to repeat program
            
               if (cAgain == 'y' || cAgain == 'Y')//repeats calculator
               {
               goto YES;  //back to menu
               }
               else if (cAgain == 'n' || cAgain == 'N')//sends to end
                           
   return 0;  
    } 
    

    printf("\n\tWould you like to calculate for another store? (y/n) ");//prompts for repeat
            scanf("%c", &cAgain);   
            
               if (cAgain == 'y'|| cAgain == 'Y')//repeats calculator upper or lower case
               {
               goto YES;  //sends user back to the begining
               }
                  else if (cAgain == 'n' || cAgain == 'N')//ends program upper or lower case
                  {
                  printf("\n\tPlease press enter to exit\t\n");  //prompts for exit
                  }
             
  return 0;
}
}

no1zson> can somebody look at my IF loop (the first one for selcting 1-3) and see where I am going wrong?

I am sure we can guess what you are trying to do, but don't you think it would be more effective if you tell us what is supposed to do and what's doing which is not the expected result?

no1zson> if storenum >=1 || if storenum <=3]

if (storenum >= 1 && storenum <= 3) {
    /* do something */
}
Comments
thanks for the tip

Switch \code with /code.
Shorten your code.
What is an IF loop? I think you mean while loop.

I hope this wasnt suppost to be your loop:

if storenum >=1 || if storenum <=3 //While Loop to Request Input of 1,2,or 3, still working on this

A while loop looks like:

while(/*condition here*/) {
    /* Code here */
}

Edited 3 Years Ago by Reverend Jim: Fixed formatting

Whoops! Double post. Sorry Aia, it took about 5 minute's to post (daniweb seems slow today).

Sorry. You are right. I am just having one of those days.

If the user selects 1, 2 or 3 then they should be sent to the CASE switch, otherwise down to the INVALID error message and forced to reenter the correct number.

Right now I am getting a compile error.
'if storenum >=1 || if storenum <=3 { switch (storenum) { case 1: printf("\nDel Mar \tSale $%.2f\tRate %.2f%%\tTax $%.2f%\t\n\n",sales, 7.25, sales*7.25/100)'
aborting compile

Hiroshe,
I started with a While loop and decided to change.

What I am now trying to do is IF 1 2 or 3, go to the appropriate CASE statement,
ELSE go to my INVALID error statement.

Don't use goto, try a function. You already have a switch in an if statement, don't make it any more complex.

Avoid fflush() and look into a replacement of scanf()

Comments
thanks for the effort

Sorry MosaicFuneral, I do not even know what that means.
If I could I would like to get it working correctly as I have it in my mind and then refine from there. I also have a few ideas in that arena, but first want to execute to see how this works.

I have adjusted my code, I think I am close but it will not compile.

if (storenum >=1 && if storenum <=3)     //While Loop to Request Input of 1,2,or 3, still working on this
    {
 	
  	switch (storenum) // simple switch which responds to corresponding menu choice with output
  }
    {
    case 1:
//Calculates and Displays Store, Sales, Tax rate, Tax for Del Mar
        printf("\nDel Mar \tSale $%.2f\tRate %.2f%%\tTax $%.2f%\t\n\n",sales, DelMar, sales*DelMar/100); //values are correct so I am leaving it this way. ahead of schedule here.
        break;
    case 2:
//Calculates and Displays Store, Sales, Tax rate, and Tax for Encinitas
        printf("\nEncinitas \tSale $%.2f\tRate %.2f%%\tTax $%.2f%\t\n\n",sales, Encinitas, sales*Encinitas/100);
        break;
    case 3:
//Calculates and Displays Store, Sales, Tax rate, and Tax for La Jolla
        printf("\nLa Jolla \tSale $%.2f\tTax %.2f%%\tTax $%.2f%\t\n\n",sales, LaJolla, sales*LaJolla/100);
        break;
    } //Storenum switch end
    }
    else
    {
    fflush(stdin);
    	printf("\nPlease enter 1,2 or 3\n");
    	
    	printf("\n\tINVALID NUMBER ENTERED! Would you like to try again? (y/n) ");//allows repeat 
            scanf("%c", &cAgain);  //scan input to repeat program
            
               if (cAgain == 'y' || cAgain == 'Y')//repeats calculator
               {
               goto YES;  //back to menu
               }
               else if (cAgain == 'n' || cAgain == 'N')//sends to end
                           
   return 0;  
    }

This is the error I see when I compile.
'if (storenum >=1 && if storenum <=3) { switch (storenum) } { case 1: printf("\nDel Mar \tSale $%.2f\tRate %.2f%%\tTax $%.2f%\t\n\n",sales, 7.25, sales*7.25/100)'
aborting compile

I caught that too PetuniaRose, I am still getting a parse error on that line though, and it seems like it should work to me.

if (storenum >=1 && if storenum <=3)     //While Loop to Request Input of 1,2,or 3, still working on this
    {
 	
  	switch (storenum) // simple switch which responds to corresponding menu choice with output
    }

So it's been many years since I tried to code in C, but I know the feeling of staring blankly at code - you wrote:

if (storenum >=1 && if storenum <=3)

It looks to me like you have an extra "if" in there - shouldn't it be

if (storenum >= 1 && storenum <= 3)

??

Comments
Much help.

Brilliant suggestion Hiroshe,
I took that out altogether, did a few quick adjustments and eliminated a lot of unneeded code.
Trouble is, now I get no output! lol
No matter what I enter I end up at INVALID NUMBER.

Any suggestions?

if (storenum == '1')
//Calculates and Displays Store, Sales, Tax rate, Tax for Del Mar
        printf("\nDel Mar \tSale $%.2f\tRate %.2f%%\tTax $%.2f%\t\n\n",sales, DelMar, sales*DelMar/100); //values are correct so I am leaving it this way. ahead of schedule here.
    else if (storenum == '2')
//Calculates and Displays Store, Sales, Tax rate, and Tax for Encinitas
        printf("\nEncinitas \tSale $%.2f\tRate %.2f%%\tTax $%.2f%\t\n\n",sales, Encinitas, sales*Encinitas/100);
    else if (storenum == '3')
 //Calculates and Displays Store, Sales, Tax rate, and Tax for La Jolla
        printf("\nLa Jolla \tSale $%.2f\tTax %.2f%%\tTax $%.2f%\t\n\n",sales, LaJolla, sales*LaJolla/100);
  
    else if (storenum <'1' || storenum >'3')
    {
    fflush(stdin);
    	printf("\nPlease enter 1,2 or 3\n");
    	
    	printf("\n\tINVALID NUMBER ENTERED! Would you like to try again? (y/n) ");//allows repeat 
            scanf("%c", &cAgain);  //scan input to repeat program
            
               if (cAgain == 'y' || cAgain == 'Y')//repeats calculator
               {
               goto YES;  //back to menu
               }
               else if (cAgain == 'n' || cAgain == 'N')//sends to end
                           
   return 0;  
    }

PetuniaRose, you and me both. I am no C programmer by a long shot.
You were right about the second IF, but my problem appears to be in my switch statement. If I take it out

{ 	
  	switch (storenum) // simple switch which responds to corresponding menu choice with output
    }

I go straight through the program executes, but goes straight to the INVALID NUMBER error no matter what I input. Leave it in and my parse error is on that line.

I didn't mean get rid of the switch-case, I ment get rid of the the if statment. Instead of having the last "else if", just use "else". Also, you have single quotes around the numbers in your if statments. That means your checking for the ascii value of 1 and 3, not the numbers 1 and 3.

Comments
Much help.

Thanks guys. Eliminating the switch ended up being the way to go. It was quicker than playing with the whole IF mess.
I still have a little syntax stuff to work out but your help is much appreciated.
I will post final code if you even care to see it. Otherwise I will just close the thread.

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