Why get the last char twice?
#include <iostream>
#include <fstream>
using namespace std;
int main (int argc, char* argv[])
{
if (argc == 1) return 0;
char c;
for (int i = 1; i < argc; i++)
{
ifstream input;
input.open(argv[i]);
while (!input.eof())
{
input >> c;
cout << c;
}
input.close();
}
return 0;
}