simple array and pointer related question

[[e-mail]]

hi all,
plz explain me.

in following code

int main()
{
	int arr[5] = {1,2,3,4,5};

	printf("\n *arr = %d", *arr);
	printf("\n *arr = %d", *(++arr));
	return 0;
}

why
printf("\n *arr = %d", *(++arr));
this line giving error: '++ needs l-value'

[WaltP]

Because arr is not a pointer. It is the address of the array and you cannot change to it.

[[e-mail]]

Thank you very much.

but what is meaning of that error: '++ needs l-value'

[shah1248]

Thank you very much.

but what is meaning of that error: '++ needs l-value'

Compiler messages can be funny sometimes. You really have to look at the code closely to figure out why it is saying so. I guess here the compiler is actually not able to change the value of the variable (since it is array name) and it thinks that it is because the lvalue for ++ operator does not exist.

[WaltP]

http://en.wikipedia.org/wiki/Value_%28computer_science%29

[[e-mail]]

Thank you all.