user enters up to 20 charachters that are of digits 1-9

so enter a number: 109832032

i need to get each charachter and convert it to an int.

so '1''2'''3''4'=1234

how do i convert it, im using arrays and a ton of if statements, but its not working

check my code

[

```
#include<iostream>
using namespace std;
int main(){
const int max=20;
char let[20];
char numb[10]={'0','1','2','3','4','5','6','7','8','9'};
int c[20]={0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};
int count=0;
for(int x=0;x<max;x++){
cin.get(let[x]);
if(let[x]=='\n'){
break;
}
if(let[x]=='0'){
c[x]=0;
}
if(let[x]=='1'){
c[x]=1;
}
if(let[x]=='2'){
c[x]=2;
}
if(let[x]=='3'){
c[x]=3;
}
if(let[x]=='4'){
c[x]=4;
}
if(let[x]=='5'){
c[x]=5;
}
if(let[x]=='6'){
c[x]=6;
}
if(let[x]=='7'){
c[x]=7;
}
if(let[x]=='8'){
c[x]=8;
}
if(let[x]=='9'){
c[x]=9;
}
count+=1;
}
int sum=0;
for(int g=1;g<count;g++){
sum=c[0];
c[0]*=10;
sum=c[0]+c[g];
c[0]=sum;
cout<<sum<<endl;
}
cout<<endl;
system("pause");
}
```

]