Modify the simulator so that it includes the jump instruction. Test your work with the following program. The first instruction jumps to the instruction at address 2, so on the second cycle your simulator should print an ALU output of 15, not 14.
0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0
0 0 0 0 0 0 0 0 1 1 1 0 0 1 1 1 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0
0 0 0 0 0 0 0 0 1 1 1 0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 0 0Jump to PostIs that binary supposed to mean something?
Because it means diddly-squat to us.
Perhaps you should read the instruction encoding manual for whatever processor you're using (real or simulated).
I really need help with this
Is that binary supposed to mean something?
Because it means diddly-squat to us.
Perhaps you should read the instruction encoding manual for whatever processor you're using (real or simulated).
This is what I decoded from it
Jump $2
Add $7 := $7 + $2
Add $8 := $7 + $2
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