Hi there,
quick (and I am sure) simple question on a program I have just created.
here's the code:

#include<iostream>
using namespace std;

int main()
{
char letter;
int counter=0;//set the counter to 0
for (letter=65; letter<=122; letter++)
{if ((((((letter==91)||(letter==92)||(letter==93)||(letter==94)
	 ||(letter==95)||(letter==96))))))continue;
counter++;//increment the counter in the loop
		if (counter==27)//counter condition
		cout<<" \n";
cout<<letter<<" ";

}
counter=0;//reset the counter
return 0;
}

what's bugging me is the counter. I included

int counter=0;

because I wante to have a space between the upper case alphabet and the lower case one, but I had to make it equal to 27 to get the space right and the letters of the alphabet are 26...why is that?
thanks

Only considering the formatting of the code,
consider a more readable alternative ..

#include<iostream>
using namespace std;

int main()
{
  char letter;
  int counter = 0; //set the counter to 0

  for (letter = 65; letter <= 122; letter++)
  {
    if(   (letter == 91)
      ||  (letter == 92)
      ||  (letter == 93)
      ||  (letter == 94)
      ||  (letter == 95)
      ||  (letter == 96)
    )
      continue;

    counter++; //increment the counter in the loop
    
    if (counter == 27) //counter condition
      cout << " \n";

    cout << letter << " ";
  }

  counter = 0; //reset the counter

  return 0;
}

When the value of the variable letter is 65, the alphabet A is displayed. When the value is 90 the variable Z is displayed. At this time the value of counter is 26. The for the values 91-96 there is no display. Then the value of letter becomes 97. Counter gets incremented to 27, we go to the next line and the letter a is displayed

Hi, yeah, you're quite right about readibility, I didn't know I could break each line like that, I thought it would have caused an error or something.

About this

When the value of the variable letter is 65, the alphabet A is displayed. When the value is 90 the variable Z is displayed. At this time the value of counter is 26. The for the values 91-96 there is no display. Then the value of letter becomes 97. Counter gets incremented to 27, we go to the next line and the letter a is displayed

I think I am following but I thought that if I say

if (counter==26)//counter condition
cout<<" \n";

the line space will be placed after the 26th character but instead it places it after character 25.

I can show you another quick example though, because I don't seem to be getting this counter business and line breaks at all.
This example is in the book I am using for C++(C++ a beginner's guide - Herbert Schildt). it goes:

#include<iostream>
using namespace std;
int main()
{
double f;
double m;
int counter;

counter=0;

for(f=1.0;f<=100.0;f++)
{
m=f/3.28;
cout<<f<<" feet is"<<m<<"meters.\n";
counter++;
if (counter==10)
{
cout<< "\n";
counter=0;
}
}

	return 0;
}

As you can see it's

if (counter==10)
{
cout<< "\n";

so here the line breaks is actually placed after 10 lines as it says in the program, whereas in my program if I say

if (counter==26)//counter condition
cout<<" \n";

the line break goes after the 25th letter...this is what I mean, and I don't understand why to have a line break after the 26th letter I have to write

if (counter==27)//counter condition
cout<<" \n";

and not

if (counter==26)//counter condition
cout<<" \n";

.
thanks

I don't understand why to have a line break after the 26th letter ...

You need to use 27 because you increment the counter before the if-statement.

oh I see,so if I place the increment after the counter I will be able to use 26. I will have a go and post the result, thanks

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