I need help with my sort. it will sort first name but when it gets to last name and DOB it wont. Please help me I tried bubble sort and it didnt work. I would like to use bubble sort.

import javax.swing.*;
import java.util.Scanner;
/**
 * @(#)program 2.java
 *
 *
 * @author ********
 * @version 1.00 2010/9/28
 */


public class program2{
    public static void main( String[] args ){
        Scanner input = new Scanner(System.in);

        int num; //This will store the number of people that the user wants to enter.
        String[][] people; //Setting the array.
        String inputString, menu_choice = "0";

        System.out.print("How many people would you like to enter?");
        num = input.nextInt();

        people = new String[num][3];
        //The rows in the array will signify the person number while column 0, holds the first name, column
        //1 holds the last name, and column 2 hold the birth date.

        inputString = input.nextLine();//Consume remaining new line
        //for loop below will get asking the question depending on how many people they have put in.
        for(int i = 0; i < num; i++)
        {
            System.out.print("What is person number " + (i + 1) + "'s fisrt name? "); // i +1 will display 1,2,3,etc of the name they need to enter.
            people[i][0] = input.nextLine();
            System.out.print("What is the person last name? ");
            people[i][1] = input.nextLine();
            System.out.print("Enter the person birth date in following order(MM/DD/YYYY)? ");
            people[i][2] = input.nextLine();
        }
        int option;
        //The while loop below will show the menu so the user can choose what to do next.
        while(!menu_choice.equals("3"))
        {
            System.out.print("Please select a option below:" + "\n Enter 1 to Display" + "\n Enter 2 for to search directory"
            + "\n Press 3 to Exit the program.");// option's to choose what to do.
            menu_choice = input.nextLine();

            if(menu_choice.equals("1"))
            { //this will be used to display the user names or DOB.
                System.out.print("Select how you would like the sort to display :" + "\n 1 to display frist name."
                    + "\n 2 to display last name." + "\n 3 to diplay DOB");
                option = input.nextInt();
                SortArray(option, people, num);
            }
            else if(menu_choice.equals("2"))
            { //Searrch for a cretain person by first, last, or DOB
                System.out.print("How would you like to serach: " +"\n 1 to serach by frist name."
                    + "\n 2 to serach by last name." + "\n 3 to serach by DOB");
                option = input.nextInt();
                SearchArray(option, people, num);
            }
            else if(menu_choice.equals("3"))// if input is 3 the program will exit
            {
                System.out.print("Thank you for using the program :)");
            }
            else
            {
                System.out.println("The data you putin is not vaild.");
            }   
        }
        System.exit(0);
    }



    public static void SortArray(int choice, String person[][], int num)
    {

        String[][] t, p;
        t = new String[1][3];// t and p is used as a temp storage.
        p = new String[1][3];
        String s;
        String d;//sorts thhe data
        boolean sort = true;

        int x, y;
        int z;
        while(sort)//sort using the while loop.
        {
            for(x = 0; x < num -1; x++)
            {
                for(y = 0,z=0; y < 3; y++,z++)
                {
                    if((y + 1) != num)
                    {
                        t[0][z] = person[z][y];
                        p[0][z] = person[z][y];
                    }
                }
                s = t[0][choice - 1];
                System.out.println (s);
                d = p[0][choice - 1];
                System.out.println(d);

                if(s.compareToIgnoreCase(d) > 0 && (x + 1) != num)
                {
                    for(x = 0; x<num; x++)
                    {
                        person[x][y] = p[0][y];
                        person[x+1][y] = t[0][y];
                    }
                }
                else
                {
                    sort = false;
                }

            } 
        }

        for(x = 0; x < num; x++)
        {
            System.out.println(person[x][0] + " " + person[x][1] + "\t" + person[x][2]);
        }
    }



    public static void SearchArray(int choice, String person[][], int num)
    {
        Scanner input = new Scanner(System.in);

        String inputString = "a";


        if(choice == 1 || choice == 2)
        {
            System.out.print("Which name would you like to serach for? ");// will ask what name to serach for.
            inputString = input.nextLine();
        }
        else if(choice == 3)
        {   // if they want to seerach by DOB
            System.out.print("Enter the DOB(MM/DD/YYYY)");
            inputString = input.nextLine();
        }
        boolean valid = true;
        if(valid)//Check that the user selected the correct option.
        {
            for(int i = 0; i < num; i++)
            {
                if(inputString.equalsIgnoreCase(person[i][choice - 1]))//When a match is found, it is printed
                {
                    System.out.println(person[i][0] + " " + person[i][1] + "\t" + person[i][2]);
                }
            }
        }
    }
}

Edited 3 Years Ago by Dani: Formatting fixed

Please edit your code and add code tags to make it more readable.
Use the upper right icon.

A comment on your coding style -
Use self documenting variable names, not single letters
s.compareToIgnoreCase(d) <<< what does this compare?

Edited 6 Years Ago by NormR1: n/a

sorry, I dont know why it didnt indent but anyways I got it to work thank you

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