Could anyone instruct me about the Python code for magic square 3*3, I got some instructions but still made no dent in program. Could anybody send me the code?

O(∩_∩)O Thanks!

here's the instrctions:

magic3

# In recreational mathematics, a magic square of order n

# is an arrangement of n^2 numbers, usually distinct

# integers, in a square, such that n numbers in all rows,

# all columns, and both diagonals sum to the same constant

# (this constant is the magic number).

# A normal magic square contains the integers from 1 to n^2.

# (From Wikipedia, the free encyclopedia.)

# Implement the function to find the arrangement of numbers

# for n=3. The returned arrangement must be a TUPLE of numbers,

# where the first 3 elements are for the first row; the

# second 3 for the second row, and the last 3 for the last row.

# For example, (1,2,3,4,5,6,7,8,9) corresponds to

# the following square:

# 1 2 3

# 4 5 6

# 7 8 9

# Hint: the magic number is always: n*(1+n*n)//2

# Hint: use itertools.permutations for brute force.

# Note: answer is not all, but how your code

# comes up with the answer.

O(∩_∩)O~