Feim Hi all,
I have this string "May 19, 2009 15:39:41.606809000" , i need to get the seconds into a double variable.
My code is like this:
double sec;
string seconds = str.substr(19,10);
istringstream(seconds) >> sec;The thing is that seconds = 41.6068090 , but sec = 41.6068
Why doesn't the number of digits is lower?
Any guess?
Thanx in advance
Edited by Nick Evan: Added CODE-tags
Lerner 582 it may be the display of the value, not the actual value itself that's the problem. Try adjusting the display with ostream modifiers like setprecision, setwidth, etc.
Feim Thanks, now it displays correctly!
But, i save this values in a file:
double sec;
double secundo;
seconds = str.substr(19,10);
istringstream(seconds) >> sec;
cout.precision(10);
cout.setf(ios::fixed, ios::floatfield);
cout << "sec: " << sec << endl;
secundo = ((min*60)+sec);
cout << secundo<< endl;
frames[i].timesec = secundo;
}
myfile.open ("Exemplo.csv", ios::out | ios::app);
myfile << "Frame.time_delta" << ";" << "Frame.timesec" << ";" << "Frame.lenght" << ";" << endl;
for(i=1; i<= k ; i++)
{
myfile << frames[i].time_delta << ";" << frames[i].timesec << ";" << frames[i].lenght << endl;
}Secundo is also displaying right, but when i save into a file the value is displayed without the .precision(10), how do i instruct to save with the same precision?
Edited by Nick Evan: Added CODE-tags
zoefschildpad myfile.precision(10); should do the trick I think, filestreams are very similar to cout and cin.
