Hi thete )Tell me please -
am I right -
if fillnumb=0 then after executing this code -
switch (fillnumb)
{
case 0:
[B] fillnumb[/B] = 1;
break;
case 1:
[B]fillnumb[/B] = 2;
break;
}fillnumb will be =2 ;
Jump to Post>fillnumb will be =2
Why would it be? If fillnumb is 0, then that falls into your case 0, which sets fillnumb to 1. A break at the end of a case terminates the switch statement, so execution won't fall through to case 1.
>fillnumb will be =2
Why would it be? If fillnumb is 0, then that falls into your case 0, which sets fillnumb to 1. A break at the end of a case terminates the switch statement, so execution won't fall through to case 1.
оk) thanks)
The following if-statement is equivalent to your switch statement. You can see from this code that Narue is correct:
if (fillnumb == 0)
fillnumb = 1;
else if (fillnumb == 1)
fillnumb = 2;thank you for good explanation, darkagn ))
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