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Solution :

For a pair of straight lines, we have,<br>
`Delta = abc+2fgh-af^2-bg^2-ch^2 = 0`<br>
In the given equation,<br>
`a = 2, b = -3,c = -1,g = -1/2, f = -2, h = k/2`<br>
So, putting these values in the above equation,<br>
`(2)(-3)(-1)+2(-2)(-1/2)(k/2)-(2)(-2)^2-(-3)(-1/2)^2-(-1)(k/2)^2 = 0`
`=>6+k-8+3/4+k^2/4 = 0`<br>
`=>k^2+4k -5 = 0`<br>
`=>k^2+5k-k-5 = 0`<br>
`=>k(k+5)-1(k+5) = 0`<br>
`=>(k-1)(k+5) = 0`<br>
`k = 1 and k = -5`, are the required values of `k`.<br>**Explain Pair of straight lines with examples.**

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