So yeah, i figured out how to write program that will print digits in reverse(with small help of the internet, put i get it). Anyway i want to write program that will print digits in their regular order.

```
def num_digits(n):
count=0
while count <= abs(n):
count = count + 1
n= abs(n)/10
return count
def print_digits(n):
while n > 0:
print n #my "plan" is to go with n/ (10**num_digits(n)) and that taking
#taking it like decimal with one decimal place and taking that value)
#For example: 123 / (10**3) = 0,123. and than fix it so that is 0,1.
#after this 0,1 * 10 = 1 and here is our 1st digit
#how u guy understand how i want this to work
#rest of code
n=n/10
print n #not quite sure for this line
```

help?

p.s. be gentle i'm learning yet