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Need a little help,

I'm trying to run a program that asks the user to enter an integer between 1-50.

If given a number between 1 and 50 then echo number then add all integer between 1 and integer entered

if user enter an integer not between 1 and 50 then just echo the number and ask the user for another number

if a noninteger is enter i need the program not to go into and fail state, instead clear the noninteger and ask the user for another integer.

To exit the loop you must press cntl-Z.

This is what I have so far: (please help, thanks)

```
#include <iostream>
using namespace std;
int main ( )
{
int number;// the integer entered
int sum =0; // the sum of numbers added
int rep = 0;
while(rep != 1)
{
cout << " Enter a positive integer (use cntl-Z to quit)" << endl;
cin >> number;
cout << " " << number << endl;
if (cin.fail())
{
cout << "Bad input, please enter another positive integer (use cnt-Z to quit)" << endl;
cin >> number;
return 0;
}
if ( number >= 1 && number <=50)//test expression
{
for(int i=1;i<=number;i++)
{
sum = sum + i;
}
cout<<"Sum is: "<< sum;
}
}
return 0;
}
```

*Edited 3 Years Ago by mike_2000_17*: Fixed formatting