Member Avatar for samreen36

i place two forms one contain 2 picturebox and 2 button and 2nd form contain 2 picturebox and one button
when insert image in 1st form it automaticaly load on 2nd form when 2nd form load.
plzzzzzzzzzzzzzz help me to do this

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  • Latest Post Latest Post by abelLazm

Dani AI

Generated

As demonstrated, passing the image information to Form2 and loading it there is a simple, effective solution that solved 's original request. A few practical improvements make that pattern more reliable in real projects: avoid Image.FromFile (it keeps the file handle open), always dispose previous Image objects to prevent GDI handle leaks, and prefer passing an Image (or a byte[]/MemoryStream) instead of a file path when the image may change or the file might be removed.

A compact VB.NET pattern that avoids file locks and cleans up resources:

' Form1: load without locking and pass a safe copy
Dim path As String = openFileDialog1.FileName
If String.IsNullOrEmpty(path) Then Exit Sub

Dim img As Image
Using fs As New IO.FileStream(path, IO.FileMode.Open, IO.FileAccess.Read)
    img = Image.FromStream(fs)
End Using

Dim copy As Image = New Bitmap(img)  ' detach from original stream
img.Dispose()
PictureBox1.Image = copy

Dim f2 As New Form2(copy)
f2.Show()
' Form2: take ownership of a clone and dispose on close
Public Class Form2
    Private ReadOnly _img As Image

    Public Sub New(ByVal img As Image)
        InitializeComponent()
        If img IsNot Nothing Then _img = CType(img.Clone(), Image)
    End Sub

    Private Sub Form2_Load(...) Handles MyBase.Load
        PictureBox1.Image = _img
    End Sub

    Protected Overrides Sub OnFormClosed(e As FormClosedEventArgs)
        If PictureBox1.Image IsNot Nothing Then
            PictureBox1.Image.Dispose()
            PictureBox1.Image = Nothing
        End If
        MyBase.OnFormClosed(e)
    End Sub
End Class

Common pitfalls and tips:

  • "Generic GDI+ error" when saving usually means the image is still in use — clone or dispose before saving.
  • When updating an already-open Form2, expose a SetImage(img As Image) method (clone inside) instead of reopening the form.
  • Always null-check and wrap file access in Try/Catch.
  • For consistent display, set PictureBox.SizeMode = PictureBoxSizeMode.Zoom.

These notes extend ’s approach with safer resource handling and are suitable when the page is viewed later or the image source changes.

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Member Avatar for abelLazm

when you show the 2nd form pass the path of loaded image in 2nd form and in form2_load event load that image in picturebox

as

//code in form 1
 String strFileName = "";
        public Form1()
        {
            InitializeComponent();
        }

        private void button1_Click(object sender, EventArgs e)
        {
            openFileDialog1.Filter = "Image FIles (*.jpg)|*.jpg|All files (*.*)|*.*";
            //openFileDialog1.InitialDirectory = @"d:/";
            openFileDialog1.Title = "Select an image file"; 
            if (openFileDialog1.ShowDialog() == DialogResult.OK)
                strFileName = openFileDialog1.FileName;
          
            if (strFileName != "")
                pictureBox1.Image = Image.FromFile(strFileName);
        }

        private void button2_Click(object sender, EventArgs e)
        {
            Form2 obj = new Form2(strFileName);
            obj.Show();
        }

//code in form 2

 String PathOfImage = "";
        public Form2(String Path)
        {
            InitializeComponent();
            PathOfImage = Path;
        }

        private void Form2_Load(object sender, EventArgs e)
        {
            pictureBox1.Image = Image.FromFile(@PathOfImage);
        }
Edited by abelLazm because: n/a
commented: Continous effort. +14
commented: Godd Logic +3
Member Avatar for samreen36

Thankes alot realy thankes thankes alot

Member Avatar for abelLazm

You are welcome :) if your problem is solved please mark this thread solved

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