How to calculate the sum & product of dis-similar numbers of an array[10].

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Last Post by Aslan89

Let's see what you have

Let's see what you have

``````using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
int i, j, k, sum, c;

sum = 0;
int[] m = new int[10];
for (k = 0; k < 10; k++)
{
Console.Write("Enter Value: ");
}

for (i = 0; i < 10; i++)
{

c = 0;

for (j = i + 1; j < 10; j++)
{

if (m[i] == m[j] && c==0)
{
sum = sum + m[i];
sum = sum + m[j];
m[j] = 0;

c++;

}
else if (m[i] == m[j])
{

sum = sum + m[j];
m[j] = 0;

}

}

}
Console.WriteLine("sum of similar numbers : " + sum);

}
}
}``````

// sum of dissimilar numbers can simply be found by subtracting the sum of similar numbers from the total sum.....

Edited by fashxfreak: n/a

``````using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{

int i, j, k, p;

p = 1;
int[] m = new int[4];
for (k = 0; k < 4; k++)
{
Console.Write("Enter Value: ");
}

for (i = 0; i < 4; i++)
{

for (j = i + 1; j < 4; j++)
{
if (m[i] == m[j])
{
m[j] = 1;
if (j == 3)
{
m[i] = 1;
}
}

}

}
for (k = 0; k < 4; k++)
{
p = p * m[k];
}
if (p == 1)
{
Console.WriteLine("Product of dis-similar numbers :  0");

}
else
{
Console.WriteLine("sum of similar numbers : " + p);
}
}
}
}``````

Let's see what you have

``````using System;

namespace ConsoleApplication5
{
class Program
{
static void Main(string[] args)
{
int[] arr = { 3, 5, 7, 1, 3, 8, 7, 1, 1, 10, 15, 32, 3 };

int sum = 0;
int mul = 1;
int count = 0;

for (int k = 0; k < arr.Length; k++ )
{
for (int i = 0; i < arr.Length; i++)
if (arr[k] == arr[i])
count++;

if (count == 1)
{
sum += arr[k];
mul *= arr[k];
}

count = 0;
}

Console.WriteLine("Sum = : {0}\nMul = : {1}", sum, mul);