How can we calculate whether a number is a power of 2 or not in a single statement without using a loop?

All the ones that I can think of use loops or don't satisfy the condition.

for eg.

The use of XOR doesn't work as it gives incorrect input.
or maybe I'm not using it in a proper manner.

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If n is a power of 2, look at the value in binary.
Then look at the binary representation of n-1

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Compare bits of n-1 with bits of n.

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If n is a power of 2, look at the value in binary.
Then look at the binary representation of n-1

ok. should i just check if it's binary representation has a single 1. but how can we implement it without a loop.

Compare bits of n-1 with bits of n.

thanks a ton.

Thank Salem, he said it first.

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