0

Hi,
I have a working C source code for implementing writing of alphanumeric characters from a 3x4 keypad, similar to a normal cell phone 3x4 keypad. However, when I want to store the characters that have been typed from the keypad as a string, the characters that are on the same key as the one that I want to type, but appear before it, are also stored. For example, when I type the word monster, the characters that are stored on the string buffer are: mmnomnpqrstdepqr.
So I can get my final string by using the indexes: 0, 3, 5, 9, 10, 12, 15.
I want to take care of this situation so that my system can automatically extract only the intended characters from the whole string buffer, after the user has typed from the keypad.
So I am asking for suggestions as to how I can do this, I don't need source code but only suggestions and/or links to where I can get some information.

2
Contributors
3
Replies
5
Views
6 Years
Discussion Span
Last Post by kings_mitra
0

Why are you storing all the characters and then getting the correct one from index, rather than storing the right one alone ??

0

The characters gets stored every time the key is pressed as long as the time-out has been reached, that is how toggling between characters on the same key takes place..

0

Correct ! But then you should replace the last character until timeout occurs.
Say, 'm' entered, timeout occured, 'm' is stored.
Then, 'm' entered, stored, 'n' entered, replaced, 'o' entered, replaced, timeout occured, 'o' is stored. So now string will be "mo" and not "mmno".
Thats it.

This topic has been dead for over six months. Start a new discussion instead.
Have something to contribute to this discussion? Please be thoughtful, detailed and courteous, and be sure to adhere to our posting rules.