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I have code (below) that opens a dialog box to either open or save a file. What I need to do though, is have the file location in the textbox next to it.

Can anyone tell me the code to do that?

protected void Browse_Click(object sender, EventArgs e)
        {
            string FileName = "ExporterOutput.txt";
            string FilePath = "C:/Users/oZ012D/My Documents/ExporterOutput.txt";
            System.Web.HttpResponse response = System.Web.HttpContext.Current.Response;
            response.ClearContent();
            response.Clear();
            response.ContentType = "text/plain";
            response.AddHeader("Content-Disposition", "attachment; filename = " + FileName + ";");
            response.TransmitFile(FilePath);
            response.Write("This is a test line.");
            response.Flush();
            response.End();
}
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Last Post by butler1233
0

Easy:

Private Sub opendialog_FileOk(ByVal sender As System.Object, ByVal e As System.ComponentModel.CancelEventArgs) Handles opendialog.FileOk
        filenamefield.Text = opendialog.FileName
    End Sub

opendialog = The file dialog
filenamefield = The textbox next to the button

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