I would like to note that this is for John Conway's game of life but I must write it in C++. I am making a 10x10 version of the game and I am using jGRASPto write the code. I am having a problem when it is reading in the starting set of data from a text doc.

code for game

#include <iostream>
#include <fstream>
#include <string>
using namespace std;


//using std::cout;
//using std::cin;
//using std::endl;
//using std::ios;
//using std::ifstream;
//using std::ofstream;


void printArray2(int array[][10], int rows, int cols);
void printArray3(int array[][10], int row, int col);


int main(void){
int a00 = 0,a01 = 0,a02 = 0,a03 = 0,a04 = 0,a05 = 0,a06 = 0,a07 = 0,a08 = 0,a09 = 0,
a10 = 0,a11 = 0,a12 = 0,a13 = 0,a14 = 0,a15 = 0,a16 = 0,a17 = 0,a18 = 0,a19 = 0,a20 = 0,
a21 = 0,a22 = 0,a23 = 0,a24 = 0,a25 = 0,a26 = 0,a27 = 0,a28 = 0,a29 = 0,a30 = 0,a31 = 0,
a32 = 0,a33 = 0,a34 = 0,a35 = 0,a36 = 0,a37 = 0,a38 = 0,a39 = 0,a40 = 0,a41 = 0,a42 = 0,a43 = 0,
a44 = 0,a45 = 0,a46 = 0,a47 = 0,a48 = 0,a49 = 0,a50 = 0,a51 = 0,a52 = 0,a53 = 0,a54 = 0,a55 = 0,
a56 = 0,a57 = 0,a58 = 0,a59 = 0,a60 = 0,a61 = 0,a62 = 0,a63 = 0,a64 = 0,a65 = 0,a66 = 0,a67 = 0,
a68 = 0,a69 = 0,a70 = 0,a71 = 0,a72 = 0,a73 = 0,a74 = 0,a75 = 0,a76 = 0,a77 = 0,a78 = 0,a79 = 0,
a80 = 0,a81 = 0,a82 = 0,a83 = 0,a84 = 0,a85 = 0,a86 = 0,a87 = 0,a88 = 0,a89 = 0,a90 = 0,a91 = 0,
a92 = 0,a93 = 0,a94 = 0,a95 = 0,a96 = 0,a97 = 0,a98 = 0,a99 = 0;



int array[10][10] = {{a00,a01,a02,a03,a04,a05,a06,a07,a08,a09},{a10,a11,a12,a13,a14,a15,a16,a17,a18,a19},
{a20,a21,a22,a23,a24,a25,a26,a27,a28,a29},{a30,a31,a32,a33,a34,a35,a36,a37,a38,a39},
{a40,a41,a42,a43,a44,a45,a46,a47,a48,a49},{a50,a51,a52,a53,a54,a55,a56,a57,a58,a59},
{a60,a61,a62,a63,a64,a65,a66,a67,a68,a69},{a70,a71,a72,a73,a74,a75,a76,a77,a78,a79},
{a80,a81,a82,a83,a84,a85,a86,a87,a88,a89},{a90,a91,a92,a93,a94,a95,a96,a97,a98,a99}};


//  printArray2(array,10,10);
int o;
int p;
int num =1;
int m;
int n;
string snum;



ifstream inClientFile("input2.dat", ios::in);


if (!inClientFile)
{
cout<<"file could not be opened"<<endl;
exit(1);
}


// snum = inClientFile.getline();
// cout<<snum<<endl;
num =inClientFile.get();
while (!inClientFile.eof())
{


for(n=0; n<10; n++)// col. number
{


for(m=0; m<10; m++)// rows number
{


array[m][n]=num;// inClientFile.get();


}


}
num = inClientFile.get();
cout<<num<<endl;
}



printArray3(array,10,10);



return 0;
}


void printArray2(int array[][10], int rows, int cols){


int i, j;


cout<<"starting life."<<endl;


for (i=0; i<rows; i++)
{
for (j=0; j<cols; j++)
cout << array[j] << " ";
cout << endl;
}
cout<< endl;
}


printArray2 is same as printArray3

the input file looks like

0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
1 1 1 1 1 0 0 0 0 0
0 0 0 0 0 1 0 0 0 0
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 1 0 0
0 0 0 0 0 0 0 0 1 0
0 0 0 0 0 0 0 0 0 1

PLEASE HELP THANK YOU VERY MUCH

Recommended Answers

All 2 Replies

It print out a 10 x 10 matrix of 49 not the input values. I got the most of the other part of the project working now.

Assuming your input file is in the form of a whitespace separated 10x10 table of ints then reading it in could be as straightforward as :

for(n=0; n<10; n++)// col. number
{
  for(m=0; m<10; m++)// rows number
  {
     inClientFile >> array[m][n];
  }
}

in your version:

for(n=0; n<10; n++)// col. number
{
  for(m=0; m<10; m++)// rows number
  {
    array[m][n]=num;
  }
}

the value of num never changes and all values of array[m][n] will be the same.

I would note in passing that, generally, rows are read in one column at a time

for()  //controls rows
  for() //controls columns

rather than columns being read in one row at a time

for() //controls columns
  for() //controls rows

but you will want to confirm you are in row major as opposed to column major mode as it is possible to do it your way. It just seems clumsier under usual circumstances.

NB: To have you code appear indented on this board like the way you write it (I hope), place code tags before and after the code section (see the FAQ if you're not sure how to do it).

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