Is there anyone who can provide VB code to open "Open With" dialogbox?



in a code module:

Public Declare Function ShellExecute Lib "shell32.dll" Alias "ShellExecuteA" (ByVal hwnd As Long, ByVal lpOperation As String, ByVal lpFile As String, ByVal lpParameters As String, ByVal lpDirectory As String, ByVal nShowCmd As Long) As Long

Sub OpenWith(ByVal xFileName As String)
    ShellExecute 0, vbNullString, "RUNDLL32.EXE", "shell32.dll,OpenAs_RunDLL " & xFileName, "", vbNormalFocus
End Sub

And then wherever you want to show it:

call openwith("somefile.txt")

Let me know how it turns out.

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Hello, DaniWeb IT Community team

Thank your very much for your replying about my problem. It works.

Best regards,


Marking thread as solved.

:) thanx for that Dani.

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