Hi,I want to write a program that calculate the increment and new salary of employee based on the average of three evaluation points.(using pass by reference/pass by value). I've done the coding but the output is wrong. I think there's a mistake on the call function.

#include<stdio.h>
float get_increment(float *a);
float get_new_salary(float  *salary);
float ave,percent,ns;

int main()
{
float i,j,total=0,ave,sum;
{
for(i=0;i<3;i++)
{
    printf("Please enter three evaluations points:");
    scanf("%f",&j);

    total+=j;
    printf("%.2f\n",total);
}
ave=total/3.00;
}
            printf("%.2f\n",ave);
            get_increment(&ave);
            printf("The increment percentage is %.2f.\n",percent);
            get_new_salary(&percent);
            printf("The new salary is %.2f\n",sum);
}

float get_increment(float *a)

{
    float percent;

   if(ave>=2.00&&ave<=2.99)
   {
       percent=0.02;
   }
   else if(ave>=3.00&&ave<=3.99)
   {
       percent=0.04;
   }
   else if(ave>=4.00&&ave<=5.00)
   {
       percent=0.06;
   }
return percent;
}

float get_new_salary(float *salary)

{
    float ns,total,percent,pay,sum;


 printf("Please enter your salary:\t");
 scanf("%f",&pay);
 ns=pay*percent;
 sum=ns+pay;

return sum;

}

Edited 3 Years Ago by Dani: Formatting fixed

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When you use a variable without passing it by reference to the function doesn't give it a new value when you return to main

for example:

printf("The new salary is %.2f\n",sum);

You never assigned a value to sum at main just because you assign a value to it from a function it doesn't mean it will retain the value when it returns to the main function since you did not pass it by reference

ns=pay*percent;

same can be said here, percent has no value at float get_new_salary function

try to pass the variables percent and sum to the functions you use them in order to assign them a value

Edited 4 Years Ago by zeroliken: n/a

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