Member Avatar for trishtren

Hello,
Iv been trying to work through some issues on binary output recently. But im having problems understanding the conversion process in java when using two's complement.

I dont understand why

System.out.println(Integer.toBinaryString(-11700));

Prints out 11111111111111111101001001001100. Shoudlnt -11700 only be 15 bits long? When i calculate it by hand and invert the bits to become twos complement it produces : 101001001001100 why does java pad out the binary with 17 bits? Is this because an integer has 32 bits and only trims off non significant 0's?

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  • Latest Post Latest Post by JamesCherrill
Member Avatar for JamesCherrill

ints always have 32 bits. When you convert to a String to display them the string conversion method supresses leading zeros.

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