help please ^^
create another array, call it ArrayNum, then store the value of NumArray in reverse order. display the value in ArrayNum.
#include <stdio.h>
int main(void)
{
int numArrays[] = {2, 67, 23, 5, 7, 34, 14, 4, 8, 62};
int ArrayNum[10];
int a;
for(a=o; a<10; a++)
{
ArrayNum[a]=numArray[9];
Printf("%d", ArrayNum[a]);
numArray[9]--;
}
}
or i could display it like this
int main()
{
int numArrays[] = {2, 67, 23, 5, 7, 34, 14, 4, 8, 62};
int ArrayNum[] = {62, 8, 4, 14, 34, 7, 5, 23, 67, 2};
for(a=o; a<10; a++)
{
printf("Value in ArrayNum\n %d", ArrayNum[a]);
}
return 0;
}
juljan30
0
Newbie Poster
phorce
131
Posting Whiz in Training
Featured Poster
2, 67, 23, 5, 7, 34, 14, 4, 8, 62};
Hey,
Think something like this is what you mean.. Obviously, change it slightly!
#include <iostream>
using namespace std;
int main(int argc, char *argv[]) {
int numArray[10] = {2, 67, 23, 5, 7, 34, 14, 4, 8, 62};
int arrayNum[10];
int num = 10;
int j=0;
for(int i=10; (i >= 0); i--)
{
arrayNum[j-1] = numArray[i];
if(j >= 10)
break;
j++;
}
cout << "Actual Order: ";
for(int k=0; (k < 10); k++)
{
cout << numArray[k] << ' ';
}
cout << endl;
cout << "Reverse Order: ";
for(int i=0; (i < 10); i++)
{
cout << arrayNum[i] << ' ';
}
}
Output: --
Actual Order: 2 67 23 5 7 34 14 4 8 62
Reverse Order: 62 8 4 14 34 7 5 23 67 2
Hope this helps you :)
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